Question

MATLAB QUESTION

Find the answer for the given application of higher order differential equation using MATLAB.

NOTE: Screenshot the MATLAB ENVIRONMENT together with the CODES and FINAL ANSWERS.

PLEASE SOLVE USING MATLAB CODE! PLEASE SOLVE USING MATLAB CODE! PLEASE SOLVE USING MATLAB CODE! Assume an object weighing 2 lb stretches a spring 6 in. Find the equation of motion if the spring is released from the equilibrium position with an upward velocity of 16 ft/sec. What is the period of the motion? ANSWER SHOULD BE: 21 1 seconds or seconds 8 4 Guaranteed upvote once done perfectly.

Answer 1

clc;clear all
syms x(t)
format short
%%The equilibrium equation is mg=kx from which we can get x=mg/k, the
%%spring displacement
%%Natural frequency in rad/s is w=sqrt(k/m)=sqrt(g/x)
%%Value of g in inch/s^2 is 386.4
%1 lb is 0.031081 slug
%Spring constant k=W/x
k=2/6; %Spring constant is lb/in
m=2*0.031081; %%mass in slugs
eom= m*diff(x,t,2)+k*x==0
omega=sqrt(386.4/6);
T=2*pi/omega %Value comes out to pe pi/4 approximately

1 2 3 4 5 6 7 clc; clear all syms x(t) format short %%The equilibrium equation is mg=kx from which we can get % x=mg/k the %%spring displacement %%Natural frequency in rad/s is w=sqrt(k/m)=sqrt(g/x) %%Value of g in inch/s^2 is 386.4 %1 lb is 0.031081 slug %Spring constant k=W/ k=2/6; %Spring constant is lb/in m=2*0.031081; %%mass in slugs eom= m*diff(x,t,2)+k*x==0 omega=sqrt(386.4/6); T=2*pi/omega %Value comes out to pe pi/4 approximately 8 9 10 11 12 13 14 15 eom(t) = 8958488321171353 - 22 012 x(t) = 0 144115188075855872 T = 0.7830