Question

Design a common-source MOSFET amplifier such that RG is a multiple of D = o.st mot (Avol 15.02 VN RL = 17kr • Choose a sinusoidal signal voltage, Vsig, with Rsig = 400 kN to use as the input in this problem. Use 2 kHz as the frequency of your sinusoidal. This is a design problem so vsig will not be unique. Use V+ = 0.8 V, k = 5 mA/V2, and VA = 80 V for your MOSFET. Assume capacitors are short in the signal circuit. Neglect channel length modulation in the Bias calculations. Draw the designed amplifier circuit with the value of DC voltage sources, Rp and/or Rs. iv. Find the Bias point of the amplifier. Find all DC node voltages. Draw the signal circuit. Include the signal source and the load in your circuit. Find the values of gm and ro for your designed circuit. ii. Find the overall voltage gain of the circuit (A = 0). V. vi. Vsig iii. Calculate and sketch the waveforms for the instantaneous (total) gate, drain and source node voltages and drain current. he only restrictions are the given ones. Show your work.

Answer 1

4 parts has been solved and solution has been attached.

are -Channel musFET) Vo O. Cison Amplifier circuit (with es configuration Given Vt = 0.8 Vlhence (we by V670, so ure (n-channes mos) assuming het we take Common source Ca G SRL circuit with RC No RS (RS=0) vag I usig n- Channel MOSFET) For de Analysis a, 6 are Open Granit hence circuit will be (For pe Analysis) Rsig= yoour Bering ( VOD Given 5 = 0.57 mA Ra VOS GX Vaa vas voltage) I k=smalu? = 58103A/0² Vt=0.8v = tn (Thresold VA so v Ra 7 multiple of 7. Us zo MOSFET, be in saturation region hence In - dk (vas- Vth = 0.57 mA het (vas-vm)2 = 2x0.57 = 0.228 5 » Vas- Ven fo.u77 Best vas- Vento (for in- Channel MOSFET to on) hence, Vas- th = for u77 v mosfetis on If, vas> Vzhe Vas-Vth > 0 quosa, Vas-uth n channel

n. ~ Was hence channel MOSFET is on (saturation) when, Vas >Vth 7 Vas- Venzo and, Nbs > Nas-ven Vth= Vt (Thres uld voltage) And Utha 0.477 i VGS 0,8 to 477 102777 Ang Now het Ra be very high het ka=7mn (multiple of 7) For MOSFET 'Ra should be very high) KUL In Loop ② we Vaa- Eq Ra- vasto hence Current 7mn as Ra= In it can Ig. So voltage prop Iq Ra is very small ecteda (in herre neglec mu) So, I Vaçe Vas = 1,2770 Any ( an have, hence using can be current FG be neglected Wirit hence (RA) in loop @ KUL now applying Vbo foro - VDs=0 for saturation region, Vos= Vbo- Ilfy z? VDs 7, Vas-ith resistance) = VA ro coutput =bo and kr I 0.57 ro =140135 kn / Any The gin of The circuit, gna dig & Vas VeszConst fp = 2 k (vas-Wth? so, ganz of Ivor-ce K(Varv) avas (28=Const

hence, gm - 58103 (or u77)= 2.385 ms Ay

The Ae ukt- diagram is shown Below (including (signal source and load esig I & + + ro og RG 3 R2 gm vgs usig vo S for Analysis, Vaa, Von VOD are Fig. ů, G are short circuited, groundeda R=7mm. it

now voltage gain Vo = 1 Arola usig clarole Vo. Vgs vo. Vgr vsig Vas Ra (voltage -devider sule usig Refrsig - 7mn 7000kn =oogus Imn +4 Doka 7000 laut you kn hence tool Vo xorgus=o.965 vo 11tho) vgs vgs

from fig 0. Vo=-goivas (8011 B11R) Vgs gm (roll R 1R) Given, R=17 kn roll R = 140.358 17 naglegt- 140.35+17 dens equivalent resistance of croll Rall) = R Then, p1- I+L R a none, Yol1 RL11B) = 15.16x Ry 15.16tRo, 1 lla kn 15.16+ro (15.16) R hence, Vo vgs gm R= gun (1. 5. 16th 15.16+ry 15.16 Ry So, vo usig ad+glish ag al.si vo - A = anul as = 0.945 gm ( 15 15:16 + Pup) 1 kan Vsig 15.16 = 2.3850153 x0,945 15:16 +R 403 = 15.02 15:16 R. 3.7 4409 2.25(15.16 +2) = 15:16 ? x 15.02 34:16 = 225.45 IB=0.151 kn Ay B

as the mos is in saturation region hente, vbs > Vas Ven vber di477 v also, Ves = Vbg-fo Be (KVL in loop 9) - her, vbs= 0.477v ( take minimum value of us to maintain a saturation) 0.477= Vbb Tore n Vbo = 0.477 & SOB = 01177+ 0.57mA xor157 kn VOD 01563 V (iu) soin: Bias Point ( ID, VDs) مبا (0.57 mA, 0.477V) And albeady - Colerlated Bir Node voltages Vpp = 0.563 (already Vas = Vaq=1,277 V Jang node voltages: No = Vas = 1,277 v us Ans cal Culated Wos= 0.477 D = Vos= 0.477 ♡ soin The circuit han already been - drawn in fig ③

S. value of you and ro is already calculated. m= 2.385ms Ars No= 140.35 kn