Question

Course Home X + Mastering Engineering Mastering X C At T=0, A Series-connected Caps X C € → C session.masteringengineering.com/myct/itemView?assignment ProblemlD=11077798&offset=next Super Mario 63 Blessed Session 6 S Sketchpad 5.1 - Dra... Calculus Volume 3 myPay Web Site Guhaul truck - Reche... M Gmail YouTube Apps The current in a 25 mH inductor is known to be -10A for t <0 and (-10 cos 400t - 5 sin 400t) e 2004 A fort > 0. Assume the passive sign convention Part A At what instant of time is the voltage across the inductor maximum? Express your answer with the appropriate units. μΑ 6 ? ta Value Units Submit Request Answer Part B What is the maximum voltage? Express your answer with the appropriate units. HA ? Talne Units Type here to search

Answer 1

out tco 2) Griven data L= 25MH. - 10A for -zoot 1 = (-10 cos godt -5 sin 400t) e Part A :- Fiat dortso Ve = L dit

34001] 4000 Sinuout - 2007 2000 cos 4007 for tao Vo von fer tzo V 29x10 zuot - 10 cos 400t -ssin 400t -rest V = 0.025 Rove? L e 100054oot - ssinyoot -roote ta V = 0.025 e 71000 Sin foot 5 l 2200+ -60 60 stuut esfert (400 in 40' [4000 5104 ont -2010 BOS 400t] - -root -wot V = 6.025 2004 [ soud sin400t] To

time for man voltage is dy a at & Co.025 ezert (stovusto yout]) -- 0.025 ( ē 20tx Sorox 4 oreos 400t - 2008 at - wot Sudoscn400t]-- wot e 2x10c5400t -10% sin400t co 2x100 cos 4oot = corsin qoot

2 = sin 400 t Coscht 2 = tanqoot tan' (2 400t = quot = 1.10714 rad t = 1. 10714 40s t= 2.7678 msec maximum voltage obtained at the instant of t = 2¢7678 m sec

Iman & Valte Part B - Vmars av t=217678 msee asig Vman = 0.025 e - 200 X 217678x103 X . x Escousin (400x217678*103)] Vman = 1.388 50 volt