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Problem 6.9 The current in a 15 mH inductor is known to be -10A fort < 0 and (-10 cos 400t – 5 sin 400t) e -2004 A fort > 0.
Problem 6.2 The voltage at the terminals of the 200 uH inductor in (Figure 1) is shown in (Figure 2). The inductor current iFigure < 2 of 2 Vs (mV) 5 0 2 t (ms)
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Solution 6.9) Griven, L= 15mH = (15 010-3) H. ilt) = (-10-09 400+ - 5 sin 400L) e +70. -2006 - 200k Part 4 e > -200 to Ves Le

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