Question

What does the following code output? int[] array = { 1, 4, 3, 6, 8, 2, 5); int sum = array[0]; Il scan the array for (int i=0; i < array.length; i++) { if ( array[i] > sum) sum = array[i]; 3 System.out.println( sum );

Answer 1

output:8
explanation:
in[] array = {1,4,3,6,8,2,5};
int sum =array[0];//now sum=1
for(int i=0;i<array.length;i++)
{
   if(array[i] > sum)
   sum=array[i];
   //i=0
   //array[0] > sum | 1 > 1 //if condition fails
   //i=1
   //array[1] > sum | 4 > 1 //if condition is true
   //so, sum =array[1] = 4
   //i=2
   //array[2] > sum | 3 > 4 //if condition fail
   //i=3
   //array[3] > sum | 6 > 4 //if condition is true
   //so, sum =array[3] = 6
   //i=4
   //array[4] > sum | 8 > 6 //if condition is true
   //so, sum =array[4] = 8  
   //i=5
   //array[5] > sum | 2 > 8 //if condition fails
   //i=6
   //array[6] > sum | 5 > 8 //if condition fails
   //so finally sum is 8
}
System.out.println(sum);//prints 8