Answer:
1):
The correct option is (C):-A variety of antibodies are produced by many B cells,but each B cell produces one type of antibody.
Explanation:
2):-
The correct option is (B):- Bicoid induces the transcription of hunchback and inhibit translation of caudal.
Explanation:
Note: As per rules I should answer only 1 but I have answered 2
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Please answer these 3 questions please. During an infection: One B cell can make more than...
BOTH QUESTIONS PLEASE. Regulation of pattern formation during development depends upon altered gene expression. The majority of factors needed to generate these patterns regulate gene expression by: Promoting alternative splicing Changing phosphorylation of target proteins Altering mRNA stability Altering transcription of target genes Promoting protein degradation Question 4 3 pts Bicoid is important for generation of the anterior-posterior axis by regulating expression of multiple genes, including hunchback and caudal. How does Bicoid regulate expression of these two genes? Bicoid induces...
please answer all 3 questions asap Question 1 3 pts Some of the genes important in embryonic development are dependent upon the maternal genotype rather than the genotype of the embryo. How does this maternal information get transmitted to the embryo? During egg development, pieces of maternal DNA are moved into the embryo to temporarily allow transcription and translation of maternal DNA During egg development, proteins transcribed and translated in maternal nurse cells are moved into the embryo During egg...
In Drosophila, nondisjunction during meiosis in the parent can result in flies with abnormal numbers of sex chromosomes. Flies with a single X and no Y are male, and those with XXY are female. Which of the following events could not give rise to a male with a single X in Drosophila? Nondisjunction at meiosis II in the female parent Nondisjunction at meiosis I in the male parent Nondisjunction at meiosis I in the female parent All of these CAN...
In Drosophila, nondisjunction during meiosis in the parent can result in flies with abnormal numbers of sex chromosomes. Flies with a single X and no Y are male, and those with XXY are female. Which of the following events could not give rise to a male with a single X in Drosophila? Nondisjunction at meiosis II in the female parent Nondisjunction at meiosis I in the male parent Nondisjunction at meiosis I in the female parent All of these CAN...
Questlon 21 3 p In Drosophila, nondisjunction during meiosis in the parent can result in flies with abnormal numbers of sex chromosomes. Flies with a single X and no Y are male, and those with XXY are female. Which of the following events could not give rise to a male with a single X in Drosophila? Nondisjunction at meiosis II in the female parent Nondisjunction at meiosis II in the male parent Nondisjunction at meiosis in the female parent All...
Answer and Explain Both! Thank You! Two WVU alums decide to have kids. Assume that the male has a sister with cystic fibrosis (CF), (an autosomal recessive disease) and that he and both of his parents are normal. What is the probability that he is a CF carrier (heterozygote)? 2/3 1/3 1/4 о 3/4 12 Question 21 3 pts In Drosophila, nondisjunction during meiosis in the parent can result in flies with abnormal numbers of sex chromosomes. Flies with a...
can u tell me if these answers are correct please!??!!! Choose the best answer for the following questions. Place your answer on the line. If your answer is not on the line.it does not count 1 Mender's discovery that characteristics are inherited due to the transmission of hereditary factors resulted from his (1) dissections to determine how fertilization occurs in pea plants (2analysis of the offspring produced from many pea plant crosses (3) careful microscopic examinations of genes and chromosomes...