Question

please answer all parts

The mass of block (m) is 30 Lb. The mass of block 4 () is 50 Lb, and the mass of block B (wa) is 75 Lb. You may neglect the masses of the pulleys, and you may assume that the blocks are initially at rest a) The equation(s) for position, velocity, acceleration, and displacement b) The displacement of the block at Bir A is pulled down a known distance of 3 c) If the friction coefficient (a), between block and its support surface, is 0.10, find the acceleration of each block (ie, a da and ac). d) The tension (F) in the cord which corresponds to the frictional condition in part (c). e) The position of block A as a function of time 1) The velocity of block A, B and C as a function of time B) Plot on the same graph the velocity of blocks A and B as a function of time. h) Show graphically how the block velocity changes as the friction coefficient varies from 0 to 0.5. Solution

Answer 1

3 for A - 2T-50 M 9A ar = 2T-50 50 g ig= Acceleration der to groavity =/2T-50 = d.ssa -(a) "A for B 4T-75- IS 98 0 (6) 14T 4T-75- 203395 Forc ac - Tom Ac 30 - - T = o = |-T=0 -0.9396 (c) from (a) and c, we get: - -50 = 1.559+ 1.869c1-(₂) from (b) and (c), we get: - - 75 = 2.339 +3.729 (vi)

(4 solvirong civ), (v) and (wi), we get in A = -8.56 ft/s² LO 9. - -0. 66 ft/s? B a = -19. Is ft/s² Motion of A A SA=3ft. YATO 56 ft) 52 Now, SA = ut + h / 2 gat² -) 3 = 0 + x 8.56xt? t = 0.044 Motion of B 0.66 ft B 0-6 AYU t=0.837S So = Upt + + - 29t² -) Sprotų x 0-66x6.8373 => S8 = 0.23 ft E Displacement of block B