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8. For an alloy with 1.25 wt% Cat temperature just below eutectoid, determine the following: a....
For a 0.84 wt% C steel just below the eutectoid temperature, calculate the following:
Material Science QuestionFor a 0.84 wt% C steel just below the eutectoid temperature,
calculate the following:The fractions of total ferrite and cementite phases, the
fractions of the proeutectoid cementite and pearlite, and the
fraction of eutectoid cementite
The structure that is typically produced after a eutectoid steel is normalized is:
The structure that is typically produced after a eutectoid steel is normalized is: 100% bainite 100% g 100% martensite 100% fine pearlite 100% coarse pearlite 100% ferrite 100% cementite
3. For hypo-eutectoid steel (say, carbon content equal to 0 .40 wt%)
3. For hypo-eutectoid steel (say, carbon content equal to 0 .40 wt%), if cool from austenite to below eutectoid temperature, calculate the relative amount of pro-eutectoid ferrite and Pearlite. What is the carbon content of the Pearlite microconstituent? What is the carbon content of the pro-eutectoid constituent? Calculate the relative amount of a and Fe3C phase in the perlite constituent. 4. For hyper-eutectoid steel (say, carbon content equal to 1.2 wt%), if cool from austenite to below eutectoid temperature, calculate the...
Q2. Below is shown the isothermal transformation diagram for a 0.45 wt% C iron-carbon alloy. List...
Q2. Below is shown the isothermal transformation diagram for a 0.45 wt% C iron-carbon alloy. List the microconstituent(s) present for the heat treatment labeled on this diagram. It is not necessary to state the proportion(s) of the microconstituents. 6 options are given for each case. Pick the correct components and briefly explain your answer. (15 points) 900 1600 HIV 500 ZA+B (c) Temperature (°C) (6) A 6 Temperature (°F) Mstart) 300M(50%) ©) b) (90%) TTTT (b) (c) '(a) 103 (b)...
Using the Animated Figure 10.40, the isothermal transformation diagram for a 0.45 wt%C steel alloy, specify...
Using the Animated Figure 10.40, the isothermal transformation diagram for a 0.45 wt%C steel alloy, specify the nature of the final microstructure in terms of the microconstituents present) of a small specimen that has been subjected to the following temperature treatments. In each case assume that the specimen begins at 845 °C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure. a) Rapidly cool to 700 degrees C, hold...
In the diagram below, what is the eutectic temperature and what is the eutectoid temperature of...
In the diagram below, what is the eutectic temperature and what
is the eutectoid temperature of steel?
A.
eutectic
temperature: 1539°C,
eutectoid
temperature:
723°C.
B.
eutectic
temperature: 723°C,
eutectoid
temperature:
1539°C.
C.
eutectic
temperature: 723°C,
eutectoid
temperature:
1130°C.
D.
eutectic
temperature: 1130°C,
eutectoid
temperature:
723°C.
In the diagram below, what is the eutectic composition and what
is the eutectoid composition of steel?
A.
eutectic
composition:
4.3
wt% C, eutectoid
composition:
0.83 wt% C.
B.
eutectic
composition:
0.83
wt% C, eutectoid...
a) Based on time-temperature-transformation (TTT) diagram in Figure 2, briefly explain and label the time-temperature paths...
a) Based on time-temperature-transformation (TTT) diagram in Figure 2, briefly explain and label the time-temperature paths to produce the following microstructures (a), (b), (c). (d), 100% coarse pearlite 50% bainite 50% martensite 50% fine 100% martensite perlite and 50% martensite (10 marks) 800 727 700 Coarse pearlite 600 a + Fe,C Fine pearlite 500 400 300 200 100 1 see I min 1 hour I day 10 102 10) 10s Time, seconds Figure 2: Time-Temperature Transformation (TTT) diagram for eutectoid...
Make a copy of the isothermal transformation diagram for an iron–carbon alloy of eutectoid composition provided...
Make a copy of the isothermal transformation diagram for an
iron–carbon alloy of eutectoid composition provided overleaf and
then sketch and label time–temperature paths on this diagram to
produce the following microstructures:
a) 25% martensite and 75% austenite
b) 100% fine pearlite
c) 25% pearlite, 25% bainite, 45% martensite, and 5%
austenite.
d) 100% tempered martensite.
800 A 1400 Eutectoid temperature 700 A 1200 A P 600 1000 500 800 AXTIS 400 A 600 300 M(start 50% 200 400 M+A...
please answer question 2,3,4 A critical feature of steel is that a considerable amount of...
please answer question 2,3,4
A critical feature of steel is that a considerable amount of carbon can be dissolved in the austenite, phase, (up to 2.14 w/o at 1147"C), whereas carbon is essentially insoluble in ferrite, Cooling from point d to e, just above the eutectoid but still in the an increased fraction of the +y region, will produce phase and a microstructure similar to that shown: the particles precinitates out in the form af an intermetallic.compound called iron-carbide...
4. (12 marks) This question pertains to the iron-iron carbide phase dingrane below 1%)() 2.11 43...
4. (12 marks) This question pertains to the iron-iron carbide phase dingrane below 1%)() 2.11 43 Ai 0.77 727"C 6.67 500 0.0218 Fe,C Weight percent carborn For a Fe-0.6 wt% C alloy at temperature just below the eutectoid. (a) calculate the fractions of total ferrite and cementite phases b) Calculate fractions of the proeutectoid ferrite and pearlite.
Material Science QuestionFor a 0.84 wt% C steel just below the eutectoid temperature,
calculate the following:The fractions of total ferrite and cementite phases, the
fractions of the proeutectoid cementite and pearlite, and the
fraction of eutectoid cementite
Q2. Below is shown the isothermal transformation diagram for a 0.45 wt% C iron-carbon alloy. List the microconstituent(s) present for the heat treatment labeled on this diagram. It is not necessary to state the proportion(s) of the microconstituents. 6 options are given for each case. Pick the correct components and briefly explain your answer. (15 points) 900 1600 HIV 500 ZA+B (c) Temperature (°C) (6) A 6 Temperature (°F) Mstart) 300M(50%) ©) b) (90%) TTTT (b) (c) '(a) 103 (b)...
Using the Animated Figure 10.40, the isothermal transformation diagram for a 0.45 wt%C steel alloy, specify the nature of the final microstructure in terms of the microconstituents present) of a small specimen that has been subjected to the following temperature treatments. In each case assume that the specimen begins at 845 °C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure. a) Rapidly cool to 700 degrees C, hold...
In the diagram below, what is the eutectic temperature and what
is the eutectoid temperature of steel?
A.
eutectic
temperature: 1539°C,
eutectoid
temperature:
723°C.
B.
eutectic
temperature: 723°C,
eutectoid
temperature:
1539°C.
C.
eutectic
temperature: 723°C,
eutectoid
temperature:
1130°C.
D.
eutectic
temperature: 1130°C,
eutectoid
temperature:
723°C.
In the diagram below, what is the eutectic composition and what
is the eutectoid composition of steel?
A.
eutectic
composition:
4.3
wt% C, eutectoid
composition:
0.83 wt% C.
B.
eutectic
composition:
0.83
wt% C, eutectoid...
a) Based on time-temperature-transformation (TTT) diagram in Figure 2, briefly explain and label the time-temperature paths to produce the following microstructures (a), (b), (c). (d), 100% coarse pearlite 50% bainite 50% martensite 50% fine 100% martensite perlite and 50% martensite (10 marks) 800 727 700 Coarse pearlite 600 a + Fe,C Fine pearlite 500 400 300 200 100 1 see I min 1 hour I day 10 102 10) 10s Time, seconds Figure 2: Time-Temperature Transformation (TTT) diagram for eutectoid...
Make a copy of the isothermal transformation diagram for an
iron–carbon alloy of eutectoid composition provided overleaf and
then sketch and label time–temperature paths on this diagram to
produce the following microstructures:
a) 25% martensite and 75% austenite
b) 100% fine pearlite
c) 25% pearlite, 25% bainite, 45% martensite, and 5%
austenite.
d) 100% tempered martensite.
800 A 1400 Eutectoid temperature 700 A 1200 A P 600 1000 500 800 AXTIS 400 A 600 300 M(start 50% 200 400 M+A...
please answer question 2,3,4
A critical feature of steel is that a considerable amount of carbon can be dissolved in the austenite, phase, (up to 2.14 w/o at 1147"C), whereas carbon is essentially insoluble in ferrite, Cooling from point d to e, just above the eutectoid but still in the an increased fraction of the +y region, will produce phase and a microstructure similar to that shown: the particles precinitates out in the form af an intermetallic.compound called iron-carbide...
4. (12 marks) This question pertains to the iron-iron carbide phase dingrane below 1%)() 2.11 43 Ai 0.77 727"C 6.67 500 0.0218 Fe,C Weight percent carborn For a Fe-0.6 wt% C alloy at temperature just below the eutectoid. (a) calculate the fractions of total ferrite and cementite phases b) Calculate fractions of the proeutectoid ferrite and pearlite.
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