Make a copy of the isothermal transformation diagram for an iron–carbon alloy of eutectoid composition provided overleaf and then sketch and label time–temperature paths on this diagram to produce the following microstructures:
a) 25% martensite and 75% austenite
b) 100% fine pearlite
c) 25% pearlite, 25% bainite, 45% martensite, and 5%
austenite.
d) 100% tempered martensite.
Homework Answers
In this solution some basic concepts of Metallurgy are used. For more information, refer to any standard textbook or drop a comment below. Please give a Thumbs Up, if solution is helpful.
Solution :
NOTE : Feel free to ask further queries. Your positive rating would be appreciated and motivate me !
Add Answer to:
Make a copy of the isothermal transformation diagram for an iron–carbon alloy of eutectoid composition provided...
1. Using the isothermal transformation diagram for an iron-carbon alloy of eutectoid composition, specify the nature...
1. Using the isothermal transformation diagram for an iron-carbon alloy of eutectoid composition, specify the nature of the final microstructure (in terms of microconstituents present and approximate percentages of each) of a small specimen that has been subjected to the following time-temperature treatments. In each case assume that the specimen begins at 760°C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure (a) Rapidly cool to 400°C, hold for...
800 1400 Eutectoid temperature 700 A 1200 600 1000 500 B 800 400 A 600 300 M(start 50% 200 400 M+A M(50%) M(90%) 1...
800 1400 Eutectoid temperature 700 A 1200 600 1000 500 B 800 400 A 600 300 M(start 50% 200 400 M+A M(50%) M(90%) 100 200 C 10-1 102 103 1 10 104 105 Time (s) Temperature (C) Temperature (°F) Rapidly cool to 625°C, hold for 10 s, rapidly cool to 450°C, hold for 10s, then quench to room temperature. % Pearlite 100 % Bainite % Martensite 100 % Austenite 0 % Tempered Martensite 10 Enter answers as a whole number...
Using the isothermal transformation diagram for an alloy steel (type 4340) specify the nature of the final microstruct...
Using the isothermal transformation diagram for an alloy steel (type 4340) specify the nature of the final microstructure (in terms of micro-constituents present and approximate percentages) of a small specimen that has been subjected to the following time-temperature treatments: In each case assume that the specimen begins at 760°C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenite structure. (a) (a) Rapidly cool to 400°C, hold for 10 seconds, and...
800 A 1400 Eutectoid temperature 700 A 1200 P 600 1000 500 A 800 400 A 600 300 M(start) 50% 400 200 M+ A M(50%) M(...
800 A 1400 Eutectoid temperature 700 A 1200 P 600 1000 500 A 800 400 A 600 300 M(start) 50% 400 200 M+ A M(50%) M(90%) 100 200 105 102 103 104 10-1 10 1 Time (s) Temperature (°C) Temperature (°F) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for the following heat treatment in the boxes below. Rapidly cool to 625°C, hold for 10s, rapidly cool to 450°C,...
phase dtransformation diagram and heat treatment. Can you answer parts a b and c please. need...
phase dtransformation diagram and heat
treatment.
Can you answer parts a b and c please. need it done in
the next 30 mins
1: Using the phase transformation diagram below, describe heat treatment procedures to produce the following from eutectoid steel at 750°C 800 1400 А Eutectoid temperature 700 A 1200 P 600 1000 N 500 -- Temperature (°C) Temperature (°F) @ B 800 400 A 600 300 50% 400 200 100 104 10-1 105 1 103 10 102 Time...
LOO Etter 700 A certain steel of eutectoid composition transforms according to the isothermal transformation curve...
LOO Etter 700 A certain steel of eutectoid composition transforms according to the isothermal transformation curve shown below. a. Describe a thermal treatment that would result in a structure having 50% pearlite and 25% bainite, and 25% martensite. 1200 1000 Tenger! 500 TO 300 200 00 MASON MO 100 b. Assuming I hold for 105 seconds, what approximate temperature do I need to quench to and hold to get 100% i. Coarse pearlite 200 10 ii. Martensite iii. Bainite
Round to the nearest 5%--no need for something like 43.2...that would become 45. If there's none of that phase form...
Round to the nearest 5%--no need for something like 43.2...that
would become 45. If there's none of that phase formed, enter a 0
(zero). If it looks close enough then it is
800 1400 Eutectoid temperature 700 1200 1000 500 800 400 600 300 M(start) 200 400 M + A M( 5096) M19096) 100 10 102 03 104105 Time (s) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for...
a) Based on time-temperature-transformation (TTT) diagram in Figure 2, briefly explain and label the time-temperature paths...
a) Based on time-temperature-transformation (TTT) diagram in Figure 2, briefly explain and label the time-temperature paths to produce the following microstructures (a), (b), (c). (d), 100% coarse pearlite 50% bainite 50% martensite 50% fine 100% martensite perlite and 50% martensite (10 marks) 800 727 700 Coarse pearlite 600 a + Fe,C Fine pearlite 500 400 300 200 100 1 see I min 1 hour I day 10 102 10) 10s Time, seconds Figure 2: Time-Temperature Transformation (TTT) diagram for eutectoid...
Describe the heat treatment scheume that would provide the following property changes to 1080 steel. Refer...
Describe the heat treatment scheume that would provide the
following property changes to 1080 steel. Refer to TTT diagram
below.
a) 100% pearlite to a miture of 50% pearlite and 50%
martensite
b) Mixture of 75% pearlite and 25% martensite to 100%
martensite
800 1400 Eutectoid temperature 700 1200 600 1000 500 800 400 600 300 M(start) M(50%) M(90%) 50% 400 200 M + A 100 200 0 10-1 102 Time (s) 10 103 10 10
Q2. Below is shown the isothermal transformation diagram for a 0.45 wt% C iron-carbon alloy. List...
Q2. Below is shown the isothermal transformation diagram for a 0.45 wt% C iron-carbon alloy. List the microconstituent(s) present for the heat treatment labeled on this diagram. It is not necessary to state the proportion(s) of the microconstituents. 6 options are given for each case. Pick the correct components and briefly explain your answer. (15 points) 900 1600 HIV 500 ZA+B (c) Temperature (°C) (6) A 6 Temperature (°F) Mstart) 300M(50%) ©) b) (90%) TTTT (b) (c) '(a) 103 (b)...
1. Using the isothermal transformation diagram for an iron-carbon alloy of eutectoid composition, specify the nature of the final microstructure (in terms of microconstituents present and approximate percentages of each) of a small specimen that has been subjected to the following time-temperature treatments. In each case assume that the specimen begins at 760°C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure (a) Rapidly cool to 400°C, hold for...
800 1400 Eutectoid temperature 700 A 1200 600 1000 500 B 800 400 A 600 300 M(start 50% 200 400 M+A M(50%) M(90%) 100 200 C 10-1 102 103 1 10 104 105 Time (s) Temperature (C) Temperature (°F) Rapidly cool to 625°C, hold for 10 s, rapidly cool to 450°C, hold for 10s, then quench to room temperature. % Pearlite 100 % Bainite % Martensite 100 % Austenite 0 % Tempered Martensite 10 Enter answers as a whole number...
Using the isothermal transformation diagram for an alloy steel (type 4340) specify the nature of the final microstructure (in terms of micro-constituents present and approximate percentages) of a small specimen that has been subjected to the following time-temperature treatments: In each case assume that the specimen begins at 760°C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenite structure. (a) (a) Rapidly cool to 400°C, hold for 10 seconds, and...
800 A 1400 Eutectoid temperature 700 A 1200 P 600 1000 500 A 800 400 A 600 300 M(start) 50% 400 200 M+ A M(50%) M(90%) 100 200 105 102 103 104 10-1 10 1 Time (s) Temperature (°C) Temperature (°F) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for the following heat treatment in the boxes below. Rapidly cool to 625°C, hold for 10s, rapidly cool to 450°C,...
phase dtransformation diagram and heat
treatment.
Can you answer parts a b and c please. need it done in
the next 30 mins
1: Using the phase transformation diagram below, describe heat treatment procedures to produce the following from eutectoid steel at 750°C 800 1400 А Eutectoid temperature 700 A 1200 P 600 1000 N 500 -- Temperature (°C) Temperature (°F) @ B 800 400 A 600 300 50% 400 200 100 104 10-1 105 1 103 10 102 Time...
LOO Etter 700 A certain steel of eutectoid composition transforms according to the isothermal transformation curve shown below. a. Describe a thermal treatment that would result in a structure having 50% pearlite and 25% bainite, and 25% martensite. 1200 1000 Tenger! 500 TO 300 200 00 MASON MO 100 b. Assuming I hold for 105 seconds, what approximate temperature do I need to quench to and hold to get 100% i. Coarse pearlite 200 10 ii. Martensite iii. Bainite
Round to the nearest 5%--no need for something like 43.2...that
would become 45. If there's none of that phase formed, enter a 0
(zero). If it looks close enough then it is
800 1400 Eutectoid temperature 700 1200 1000 500 800 400 600 300 M(start) 200 400 M + A M( 5096) M19096) 100 10 102 03 104105 Time (s) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for...
a) Based on time-temperature-transformation (TTT) diagram in Figure 2, briefly explain and label the time-temperature paths to produce the following microstructures (a), (b), (c). (d), 100% coarse pearlite 50% bainite 50% martensite 50% fine 100% martensite perlite and 50% martensite (10 marks) 800 727 700 Coarse pearlite 600 a + Fe,C Fine pearlite 500 400 300 200 100 1 see I min 1 hour I day 10 102 10) 10s Time, seconds Figure 2: Time-Temperature Transformation (TTT) diagram for eutectoid...
Describe the heat treatment scheume that would provide the
following property changes to 1080 steel. Refer to TTT diagram
below.
a) 100% pearlite to a miture of 50% pearlite and 50%
martensite
b) Mixture of 75% pearlite and 25% martensite to 100%
martensite
800 1400 Eutectoid temperature 700 1200 600 1000 500 800 400 600 300 M(start) M(50%) M(90%) 50% 400 200 M + A 100 200 0 10-1 102 Time (s) 10 103 10 10
Q2. Below is shown the isothermal transformation diagram for a 0.45 wt% C iron-carbon alloy. List the microconstituent(s) present for the heat treatment labeled on this diagram. It is not necessary to state the proportion(s) of the microconstituents. 6 options are given for each case. Pick the correct components and briefly explain your answer. (15 points) 900 1600 HIV 500 ZA+B (c) Temperature (°C) (6) A 6 Temperature (°F) Mstart) 300M(50%) ©) b) (90%) TTTT (b) (c) '(a) 103 (b)...
Most questions answered within 3 hours.
-
A flea is able to jump straight up about 0.58 m. It has been
said that...
asked 2 minutes ago -
For a digital communication system,
(i) if the energy per bit is 12 dB and the...
asked 8 minutes ago -
Questions 5 – 7 use the following setup.
Summit Systems will pay a dividend of $1.50...
asked 7 minutes ago -
Annuities are used to: a. Provide cash management services to
small businesses. b. To provide tax...
asked 16 minutes ago -
I need help with my accounting questions and was wondering if
you could help me?
1....
asked 11 minutes ago -
A monetary advantage foregone due to limited resources is known
as:
A. Standard Cost
B. Life...
asked 16 minutes ago -
Is Indirect Labor part of Fixed Overhead
Costs?
I have to calculate the Overhead Allocation Rate...
asked 18 minutes ago -
This assignment is mainly to practice Selection programming
structure. That is IF ... THEN ... ELSE...
asked 17 minutes ago -
MOMENTUM
What's the difference between
m1v2 =
m1v2 &
m1v1 + m2v2
= m1v1' +
m2v2'...
asked 38 minutes ago -
When a sample of gas initially at 22.5C and a volume of 4.56 L
was expanded...
asked 39 minutes ago -
For the normal distribution, the mean plus and minus one
standard deviation will include about what...
asked 49 minutes ago -
Green Thumb, a manufacturer of lawn care equipment, has
introduced a new product. The anticipated demand...
asked 55 minutes ago