Question Details SCalcET8 5.3.504.XP.MI 12. Use Part 1 of the Fundamental Theorem of Calculus to find...
-/1 POINTS SCALCET8 5.3.503.XP. Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. 96) = [ x2+3 dx g'(N) = Need Help? Read It Talk to a Tutor
Use Part 1 of the Fundamental Theorem of Calculus 33 to find the derivative of g(x) = ſ et dt. Show your In x work in the PDF version of the test. e* dt. Show your
(1 point) Use Part I of the Fundamental Theorem of Calculus to find the derivative of cos(t2+t)dt n'(z) = (1 point) Use Part I of the Fundamental Theorem of Calculus to find the derivative of cos(t2+t)dt n'(z) =
Section 5.3 The Fundamental Theorem of Calculus 1. Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. (a) h(x) = 0arctan de. Jln. (b) g(x) = JY 1 + 73 dt.
(4 points) Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. (6 sin^(t) + 2) dt g'(x) =
help please Evaluate the definite integral using the Fundamental Theorem of Calculus. (1+ (1 + 14х5) dx Use The Fundamental Theorem of Calculus and the antiderivative found in Step 2 to evaluate the definite integral. fo* (2 + 14x5) dx = = (x+3x0916 (1+](O* )-( O*+O) “) 10 3
Using part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. 11. (21 points) Using part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. (a) f(x) = [ 71 – dt (b) $(a) = Sie a
Use the Fundamental Theorem of Calculus and the chain rule to find a derivative Question If F(x)=∫4x522ln(t2) dt, what is F′(x)? (Do not include "F′(x)=" in your answer.) Sorry, that's incorrect. Try again? Use the Fundamental Theorem of Calculus and the chain rule to find a derivative Question If F(x) = 1 2 dt, what is F' (2)? (Do not include "F'(x) ="in your answer.) In (t2) Sorry, that's incorrect. Try again? FEEDBACK VIEW ANSWER SUBMIT
tion 5 sinx Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function h(x) 3int dt h'(x) = 3 cos(x)In(sinx) - h'(x) = 3 in (cos(x)s in(x))+ 1m3) - h'(x)=3\n(sin(x)cos(x)) - 31nYX h'(x) - 3sin(x) 31n(7) cosx 2 n'(x) = () - 3cos(x) 3inx sinx x h"(x) = 3sin(x)in(cosx) + 3inky 2x
11. DETAILS SCALC8 4.3.515.XP. Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. h(x) = √5+3 dr h'(x) Submit Answer