Market demand: P=1200-5Q where Q= q1 +q2 +q3
a) C(qi)=180qi
For firm one,profit=Pq1-C(q1 )= q1(1200-5(q1 +q2 +q3 )) -180q1
For maximizing profit,we differentiate it with respect to q1 and equate to 0
we get 1200-10q1 -5q2 - 5q3 -180=0
we get (1200-5q2 -5q3)-180=10q1
q1 =102-1/2q2 -1/2q3
Similarly for other 2 firms we will get
q2 =102-1/2q1 -1/2q2
and
q3 =102-1/2q1-1/2q2
From all 3 we get q1=q2 =q3=Q/3
we get
Q/3=102-Q/6-Q/6
Q=102*3/2=153 and total profit for each firm is (1200-5Q)Q/3-180Q/3=13,005
b) For part 2
so profit (1200-5Q)q1 -180q1
differentiating we get 1200-10q1 -5q2 -180=0
q1 = 102- 1/2q2
Like before we get a similar function for firm 2(combination of firm 2 and 3) and so Q=Q/2
Q/2=102-Q/4
Q=102*4/3=136 and q1=q2 =68
Profit=(1200-5Q)q1 -180q1 =23,120 which is less than 2*13,005=26,010 and so it doesn't make sense to merge firms
c) For stackelberg equiilibrium,first we find q1 as a function of q2(which will be decided by the first mover)
we get q1 = 102- 1/2q2 as before
Now for the leader,we will substitute this function and then maximize the profit
(1200-5(q2 +102- 1/2q2 ))q2-180q2
Differentiating and equating to 0 we get
q2 =102
and q1= 102-51=51
now q2 =102 for first mover and q1=51
Profit for firm 2=26,010 and profit for firm 1= 13,005 which is similar to profit for firm 1 and combination of profits of firm 2 and 3 in the first case
d) You can find this similar to case b) by adjusting the Cost function of the second firm from 180q2 to 90q2 and thus find the profit maximization of each seperately and then find q1 and q2.
Hope this helps,please comment if you would prefer me to solve the
last one too.
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