Describe the heat treatment scheume that would provide the following property changes to 1080 steel. Refer to TTT diagram below.
a) 100% pearlite to a miture of 50% pearlite and 50% martensite
b) Mixture of 75% pearlite and 25% martensite to 100% martensite
Homework Answers
Firstly, a sample should be soaked at eutectoid temperature (723oC) for 2 hours to obtain fully homogenised microstructure. Further transformation will depend on holding temperature and cooling rate, as explained below:
Holding above nose temp. (550oC) : Pearlitic structure
Holding below nose temperature: Bainitic structure
Quenching(Faster cooling): Martensitic structure
To acheive a combination of microstructure, holding time is a crucial parameter with temperature.
TTT should observed carefully to decide processing temp and time to get desired microstructure.
Add Answer to:
Describe the heat treatment scheume that would provide the
following property changes to 1080 steel. Refer...
Round to the nearest 5%--no need for something like 43.2...that would become 45. If there's none of that phase form...
Round to the nearest 5%--no need for something like 43.2...that
would become 45. If there's none of that phase formed, enter a 0
(zero). If it looks close enough then it is
800 1400 Eutectoid temperature 700 1200 1000 500 800 400 600 300 M(start) 200 400 M + A M( 5096) M19096) 100 10 102 03 104105 Time (s) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for...
Make a copy of the isothermal transformation diagram for an iron–carbon alloy of eutectoid composition provided...
Make a copy of the isothermal transformation diagram for an
iron–carbon alloy of eutectoid composition provided overleaf and
then sketch and label time–temperature paths on this diagram to
produce the following microstructures:
a) 25% martensite and 75% austenite
b) 100% fine pearlite
c) 25% pearlite, 25% bainite, 45% martensite, and 5%
austenite.
d) 100% tempered martensite.
800 A 1400 Eutectoid temperature 700 A 1200 A P 600 1000 500 800 AXTIS 400 A 600 300 M(start 50% 200 400 M+A...
phase dtransformation diagram and heat treatment. Can you answer parts a b and c please. need...
phase dtransformation diagram and heat
treatment.
Can you answer parts a b and c please. need it done in
the next 30 mins
1: Using the phase transformation diagram below, describe heat treatment procedures to produce the following from eutectoid steel at 750°C 800 1400 А Eutectoid temperature 700 A 1200 P 600 1000 N 500 -- Temperature (°C) Temperature (°F) @ B 800 400 A 600 300 50% 400 200 100 104 10-1 105 1 103 10 102 Time...
800 A 1400 Eutectoid temperature 700 A 1200 P 600 1000 500 A 800 400 A 600 300 M(start) 50% 400 200 M+ A M(50%) M(...
800 A 1400 Eutectoid temperature 700 A 1200 P 600 1000 500 A 800 400 A 600 300 M(start) 50% 400 200 M+ A M(50%) M(90%) 100 200 105 102 103 104 10-1 10 1 Time (s) Temperature (°C) Temperature (°F) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for the following heat treatment in the boxes below. Rapidly cool to 625°C, hold for 10s, rapidly cool to 450°C,...
Austenite Pearlite Question 3 (24 pts): We are interested in performing different heat treatments to an...
Austenite Pearlite Question 3 (24 pts): We are interested in performing different heat treatments to an iron-carbon alloy of eutectoid compostion. Use the provided Temperature-Time Transformation (TTT) and Continuous Cooling Transformation (CCT) diagrams to specify the nature of the final microstructure in terms of microconstituents present and approximate percentages) of a small specimen that has been subjected to the following heat treatments. In each case, assume that the specimen begins at 760°C and that it has been at this temperature...
6.8. The heat treatments noted below are carried out in 1080 steel. In each case what phases will...
Phase, TTT, and CCT diagrams provided
6.8. The heat treatments noted below are carried out in 1080 steel. In each case what phases will be present at the end of the treatment? a. Austenitize at 750 deg C; quench to 0 deg C in 1s. b. Austenitize at 750 deg C; rapid quench to 650 deg C; isothermally anneal for 1000 s; quench to 0 deg C in 1s c. Austenitize at 750 deg C; very rapid quench to 250...
this is the TTT curve Given a plain carbon steel which has 8 % primary (or...
this is the TTT curve
Given a plain carbon steel which has 8 % primary (or pro eutectoid) carbide, determine both overall carbon content and ferrite content. a. Assume that the steel was at equilibrium just above the eutectoid temperature and then cooled immediately to 600°C and held for 5 seconds, then quenched. What microconstituents would there be in the structure and how much of each? (Assume the cooling behavior follows the TTT curve shown) 800 А Eutectoid temperature 1400...
800 1400 Eutectoid temperature 700 A 1200 600 1000 500 B 800 400 A 600 300 M(start 50% 200 400 M+A M(50%) M(90%) 1...
800 1400 Eutectoid temperature 700 A 1200 600 1000 500 B 800 400 A 600 300 M(start 50% 200 400 M+A M(50%) M(90%) 100 200 C 10-1 102 103 1 10 104 105 Time (s) Temperature (C) Temperature (°F) Rapidly cool to 625°C, hold for 10 s, rapidly cool to 450°C, hold for 10s, then quench to room temperature. % Pearlite 100 % Bainite % Martensite 100 % Austenite 0 % Tempered Martensite 10 Enter answers as a whole number...
a) Based on time-temperature-transformation (TTT) diagram in Figure 2, briefly explain and label the time-temperature paths...
a) Based on time-temperature-transformation (TTT) diagram in Figure 2, briefly explain and label the time-temperature paths to produce the following microstructures (a), (b), (c). (d), 100% coarse pearlite 50% bainite 50% martensite 50% fine 100% martensite perlite and 50% martensite (10 marks) 800 727 700 Coarse pearlite 600 a + Fe,C Fine pearlite 500 400 300 200 100 1 see I min 1 hour I day 10 102 10) 10s Time, seconds Figure 2: Time-Temperature Transformation (TTT) diagram for eutectoid...
Given a plain carbon steel which has 8 % primary (or pro eutectoid) carbide, determine both...
Given a plain carbon steel which has 8 % primary (or pro
eutectoid) carbide, determine both overall carbon content and
ferrite content. Assume that the steel was at equilibrium just
above the eutectoid temperature and then cooled immediately to
600ºC and held for 5 seconds, then quenched. What microconstituents
would there be in the structure and how much of each? (Assume the
cooling behavior follows the TTT curve shown)
800 Eutectoid temperature 1400 700 А 1200 600 1000 500 B...
Round to the nearest 5%--no need for something like 43.2...that
would become 45. If there's none of that phase formed, enter a 0
(zero). If it looks close enough then it is
800 1400 Eutectoid temperature 700 1200 1000 500 800 400 600 300 M(start) 200 400 M + A M( 5096) M19096) 100 10 102 03 104105 Time (s) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for...
Make a copy of the isothermal transformation diagram for an
iron–carbon alloy of eutectoid composition provided overleaf and
then sketch and label time–temperature paths on this diagram to
produce the following microstructures:
a) 25% martensite and 75% austenite
b) 100% fine pearlite
c) 25% pearlite, 25% bainite, 45% martensite, and 5%
austenite.
d) 100% tempered martensite.
800 A 1400 Eutectoid temperature 700 A 1200 A P 600 1000 500 800 AXTIS 400 A 600 300 M(start 50% 200 400 M+A...
phase dtransformation diagram and heat
treatment.
Can you answer parts a b and c please. need it done in
the next 30 mins
1: Using the phase transformation diagram below, describe heat treatment procedures to produce the following from eutectoid steel at 750°C 800 1400 А Eutectoid temperature 700 A 1200 P 600 1000 N 500 -- Temperature (°C) Temperature (°F) @ B 800 400 A 600 300 50% 400 200 100 104 10-1 105 1 103 10 102 Time...
800 A 1400 Eutectoid temperature 700 A 1200 P 600 1000 500 A 800 400 A 600 300 M(start) 50% 400 200 M+ A M(50%) M(90%) 100 200 105 102 103 104 10-1 10 1 Time (s) Temperature (°C) Temperature (°F) Using the above TTT diagram for the eutectoid composition of steel, enter the relative amount of each microstructure formed for the following heat treatment in the boxes below. Rapidly cool to 625°C, hold for 10s, rapidly cool to 450°C,...
Austenite Pearlite Question 3 (24 pts): We are interested in performing different heat treatments to an iron-carbon alloy of eutectoid compostion. Use the provided Temperature-Time Transformation (TTT) and Continuous Cooling Transformation (CCT) diagrams to specify the nature of the final microstructure in terms of microconstituents present and approximate percentages) of a small specimen that has been subjected to the following heat treatments. In each case, assume that the specimen begins at 760°C and that it has been at this temperature...
Phase, TTT, and CCT diagrams provided
6.8. The heat treatments noted below are carried out in 1080 steel. In each case what phases will be present at the end of the treatment? a. Austenitize at 750 deg C; quench to 0 deg C in 1s. b. Austenitize at 750 deg C; rapid quench to 650 deg C; isothermally anneal for 1000 s; quench to 0 deg C in 1s c. Austenitize at 750 deg C; very rapid quench to 250...
this is the TTT curve
Given a plain carbon steel which has 8 % primary (or pro eutectoid) carbide, determine both overall carbon content and ferrite content. a. Assume that the steel was at equilibrium just above the eutectoid temperature and then cooled immediately to 600°C and held for 5 seconds, then quenched. What microconstituents would there be in the structure and how much of each? (Assume the cooling behavior follows the TTT curve shown) 800 А Eutectoid temperature 1400...
800 1400 Eutectoid temperature 700 A 1200 600 1000 500 B 800 400 A 600 300 M(start 50% 200 400 M+A M(50%) M(90%) 100 200 C 10-1 102 103 1 10 104 105 Time (s) Temperature (C) Temperature (°F) Rapidly cool to 625°C, hold for 10 s, rapidly cool to 450°C, hold for 10s, then quench to room temperature. % Pearlite 100 % Bainite % Martensite 100 % Austenite 0 % Tempered Martensite 10 Enter answers as a whole number...
a) Based on time-temperature-transformation (TTT) diagram in Figure 2, briefly explain and label the time-temperature paths to produce the following microstructures (a), (b), (c). (d), 100% coarse pearlite 50% bainite 50% martensite 50% fine 100% martensite perlite and 50% martensite (10 marks) 800 727 700 Coarse pearlite 600 a + Fe,C Fine pearlite 500 400 300 200 100 1 see I min 1 hour I day 10 102 10) 10s Time, seconds Figure 2: Time-Temperature Transformation (TTT) diagram for eutectoid...
Given a plain carbon steel which has 8 % primary (or pro
eutectoid) carbide, determine both overall carbon content and
ferrite content. Assume that the steel was at equilibrium just
above the eutectoid temperature and then cooled immediately to
600ºC and held for 5 seconds, then quenched. What microconstituents
would there be in the structure and how much of each? (Assume the
cooling behavior follows the TTT curve shown)
800 Eutectoid temperature 1400 700 А 1200 600 1000 500 B...
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