Question

A ski jumper starts with a horizontal take off velocity of 30 mis and lands on a straight landing hill inclined at 30° Determine the time between take-off and landing the length of the jump and the maximum vertical distance between the jumper and the landing hill Vo 300 The time between take-off and landing is S. Round the final answer to two decimal places) The length of the purgis m (Round the final answer to one decimal place.) The maximum vertical distance between the jumper and the landing hills m. (Round the final answer to two decimal places)

Answer 1

Solution's »V=3umis glino glasbo 70 o Now this inclined projectile motion to the normal projectile emotion with gx = glinzu and yy = -9 Cos 30 converting P gsinzo 196030 V=30ml 30° d- Un = Vcos 30 = 30 x 3 = 30 x 3 = 1553 = 25.98 mis non Uy = Vlin 30 = 30x1 = 80x1 = 15mis 20 In-y-direction Vy = at Point P and time taken be to Vy = y + gt 15- Glosbo(t) 02

15 [g lod Bolt t 15 = 15 glosso g. 6 x 63 | t= 1.765 seconds & total time between take cefs and T= 2x1.765 landing= at T= 3.53 seconds In a direction d= Uxt + St used will be T= 3:53} d = (183) (3:53) + 4 x3843x 3-83)2 + 12 gx t² allagg d 91.71 + 30-56 122.27 m Sin 30 h to 30 ha d sinzo h = 61.13m