Question

< Homework 8 Fundamental Problem 18.11 6 of B I Review The 48-kg rod is released from rest when 0 = 45°, (Figure 1) Part A Determine the angular velocity of the rod when 8 = 0°. The spring unstretched when A=45". Express your answer to three significant figures and include the appropriate units. HHA ? Value Units Figure 1 of 1 > Submit Request Answer Provide Feedback Next > 1.5 m B k = 300 N/m

Answer 1

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Solection : Given that HOSS of the rood is kg © : 45° Nghe A liet datum line as shown, Datum when o=45 G is then tot al potential energy MMMM B al position (Initial) K: 300 pm V,-0 when 0 = 0 , then V2 Gravitational PE + Elastic PE mght 488.9.81(1.5 snus") + 5 X 300 (1.5-1.500545 °) 1/2 kox? V2 499.44 * 28,95 -470,49 Nom Initial Kinetic éneligy. CT) = 0 when o = 45° final kinetic energy CT2) - x 48 x V G2 + x x48x (1.5)*6.2 2 2 Tz 24.VG2 + 2.813 62 VG. YG I fex Wed 0.15 tcinus We 0.75 W2 ♡ 2 T2 24 x 0.5625 W2 + 2.813 WA? = 16.313 we Now, applying cons.of energy, Titu Tz + V2 0+0 - 16.313 W2P-470,79 lug = 5.372 gad/sec