Find if the following problems are algorithmically decidable and prove that your answers are correct.
Given three context-free languages N, L and M, find if the language (L⋂N)⋃(N⋂M) is empty
Please help.
Answer) Yes given problem is algorithmically decidable.
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Find if the following problems are algorithmically decidable and prove that your answers are correct. Given...
determine if the language is regular, context-free, Turing-decidable, or undecidable. For languages that are regular, give a DFA that accepts the language, a regular expression that generates the language, and a maximal list of strings that arc pairwise distinguishable with respect to the language. For languages that are context-free but not regular, prove that the language is not regular and either give a context- free grammar that generates the language or a pushdown automaton that accepts the language. You need...
determine if the language is regular, context-free, Turing-decidable, or undecidable. For languages that are regular, give a DFA that accepts the language, a regular expression that generates the language, and a maximal list of strings that are pairwise distinguishable with respect to the language. For languages that are context-free but not regular, prove that the language is not regular and either give a context- free grammar that generates the language or a pushdown automaton that accepts the language. You need...
Consider the following decision problems. Indicate which of these problems are undecidable and which are decidable. For decidable problems, sketch an algorithm to decide/solve the problem; for undecidable problems, justify why they are undecidable. To decide whether a PDA accepts the empty string. To decide whether the languages accepted by two context-free grammars have strings in common.
2. (50 pts) Given three context-free languages N, L and M, find if the language (LON)U(NOM) is empty.
Please also note that there might be multiple answers for each question. Q1: Which of the following claims are true?* 1 point The recognizable languages are closed under union and intersection The decidable languages are closed under union and intersection The class of undecidable languages contains the class of recognizable languages For every language A, at least one of A or A*c is recognizable Other: This is a required question Q2: Which of the following languages are recognizable? (Select all...
1. (50 pts) Given two context-free languages L and M, find if the language LUM is empty.
Formal Languages & Automata Theory 1411372 Pages 133,134 Problems: 7(a,b), 8 (b,c) 5.1 CoNTEXT-FREE GRAMMARS 133 EXERGISES 7. Find context-free grammars for the following languages (with n 2 0, m 0) (a) L = {a"b"": n < m + 3).
Automata Theory I've given my answer to 3d. Is it correct? If not, please correct it. Thanks 3. Context-free languages are useful for the definition of programming languages. For example, we have looked at grammars for defining Lisp and C. (a) Give a context-free language that is not regular, establishing the added power of CFL (b) What language is accepted by the following grammar: (c) Build a context-free grammar for the language (wb w-wR, k 0 a,by (d) Build a...
SUBJECT:THEORY OF COMPUTATION CAN SOMEONE PLEASE HELP ME I HAVE POSTED IT REPEATEDLY AND I KEEP GEETING INCOMPLETE / INCORRECT ANSWER . I WILL GIVE YOU A HIGH REVIEW IF YOU HELP ME AND IT IS DONE PROPERLY ! Note: Please show/explain all cases clearly for the pumping lemma and describe how your Turing machine works for each state transition. Problem 1: Non-context-free languages and Tining Machine Models B5] context-free: 쉑: Use the pumping lemma for context-free languages to show...
There are two correct answers... Incorrect Question 8 0/4 pts In performing the mapping reduction from ATM to RETm, we built a machine M' that took string x as an input. Machine M' was defined in such a way that (pick two answers below) Note: RETm is the set of TM that represent regular languages If M does not accept w, then the language of M' is context-free and equal to {0"1" : n>0} The language of M' is always...