Question

If the perimeter of a rectangle is 40 cm and the area is 84 square cm, then what are the dimensions of the rectangle?

The width, or shorter side is ___cm

The length, or longer side is ____ cm

Answer 1

Let e be the length of the rectangle & b be the breadth of the rectangle Area of rectangle - lxb. & p be the perimeter of the rectangle then p=2(l+b) Given p= 40 40=216+b) => l+b=20 l=20-b-0 А =l.b 84 =80-b) b 84 = 200- b²- zob+84=0 3214b-66+84 =0 => blb-14)_6 (6-14=0 (b-14) (6-6)=0 6=6, b=14 If b=6, then l=20-6=14 If b=14, then l=20-14 = - 6 Here b is breadth or width b=6cm l=14 cm width or shorter side is 6 cm length or longer side is 14 cm