Question

1 5. Consider a thin cantilever loaded as shown in Fig. P5. Assume that the bending Mzy stress is given by Ox=- = -2x2y and o; = Txy Tyz = 0. What will be the stress componeent in terms of x and y? (a) Oy = 2 (3hºy – y2 – 2h3), (b) oy = 8 (3h²y – y3 – 2h3), (c) 0y = (3h2y – y3 – 2h²), (d) Oy (3hy – y3 – 2h3), (e) none of above p = 61 2h Z 0 t- 2 у Fig. P5 Fig. P6

Answer 1

soin! Given that; бх L n2y Р aІ дох 2 Zя + 2 Әр 24 + x = 0, → Stress component of this cantilever дох + TZxЧ Ч +0 = 0 2х ƏZхч - 2 ( 4 ) ә9 — P4 I exy = Рич2. + f(x) 2T (EN) 8=6 ( pry² + focus » ) h = 0 = 0, І substinen b reting for y; ( Рич? + см)) чен І ри, 2 + Jix) = 0 ат ficas= Рx, 2 2 І Now the Streu component Exy Zxy = ат Puu? + си ) exy = puy? puna CS Scanned with IamScarater

Try = - Pr Ch²-y) thin cantieren si Strea componen 269 2 Zлч og - о. + tfy дх OZха Ә69 га + + 7 = 0, ах ОТяч 264 да + 0 = Әх 2 да - -=(-, -4°5) Pchy?) ory 29 21 Р 04 = 9 (-*) + (+) 21 ( льод, а (64) »ь ( 4 (к? с») ) =h - о. 2 * ) + + Рыс к?- ) +h c») = 0 . ск) = Вh (2) = 22 - рь 3 31 Now, the Strea component oy na 2 09 = Р 21 8 (h ЭТ 4*)- Ph? (зку - з P 3 С 3T 2 - Ans. 6I ба P(зка-43-2° ) option (6) Ġ correet. CS Scanned with CamScanner