Question

(a) Identify ALL zero-force members, if any, in the two trusses shown below: 10 kip 41 4 ft D 4 ft 10 kip G 1 4 ft B 600 lb 12 ft

Answer 1

salution & find F s 1 All zero & Good2 Tahu Tarung 095 fources Goojale C A Goodb B Goods Goulb Conviden Joint FED T So, I FED =) olf {5229 F9-20.06 Conxider Join & Fj30, [FEC70] & rezo, FEF=20 FEE Condensoint @! Styzo Ferf FEC [FCF) 600 J2 26. Ebe 600 16 T Erto, FBC foc Goula Consider soint 6 Frag God JZ St] $550 Fra so Fag? FIDE FCE FEF=FBF 2016 FFA Nooo fa

A 4.ft salution find all 10 kib zero force memberi 352-70, H 320 kib şFy20) RHARIO LMH0 RIX12 = (10X16) +foxD) FRI 20 kipa Lokib RH 20 kb 1720kxkk EEST EEST 16.67K & 161 9 4 fut *- 4fut VTI 13:33 DUZI kib 4193kB eft 15kg L2 fit -PH2o kop RI320 kb -FHA 7FHG THI Anele 20 Considen somt Ai & Foto F49206 +15=20510 Enax gi 179 FHG 7 41939b0 R-Fy zo FHF +4193XL-2020 179 TFHFƏ 17.781xbet) 45, 97 4 20 o FIH 20 & Foz consider point 6 $ Fy90 FIG Angle FIG smo, +2070 5 40 FIGX53-20-(FI67.25 kib FIH=25*3 20, [FIH915.kxbo Consider soint. FAC apo + 10 = 0 Fac*33-10 TFA 16.67 KxD JO Sly 3, F43- 16167x420 ( 591829 13:33 ksb / s Ş-512) 10 Ene FAB

16167 201 017 // FED Consider soint@ & F 20 FCE Copaz - Faq CQ4 +16,67 g -10 FCE - FCD - 16167 $907 Fey Sm0,+ FCE SMO; +16067 fm0990 Foot FCE - 16.67 from equation and FCE) 16.67 Kip FCD = o kep Contiden Joint 13133 1 $50 PE OKXD & Fyz) o, D *FDE FDE 13:33 Kilo FDE Condider soint Ô 13133 & Fy =) o zFFE 10 22 Anal >FFG 17178 2013 4 FFE SM027 18133–1717820 FFE 08:03 K IFFE= 8:02K & Foo FFG + 8102 C4 Q2 + 10 = 0 FFG 16 +675K d2 6 so EBC FCD FEDE okie