When graph touched x axis and bounce back then multiplicity of zero is even when it crosses then odd
At -2,4 graph crosses x axis so multiplicity odd
At 2 multiplicity even
f(x)=a (x+2)(x-2)^2(x-4)
Now at x=1,f(x)=-9/8
so a= 1/8
f(x)=(1/8)(x+2)(x-2)^2(x-4)
Option c is right
In the graph below, the coordinates of the indicated point are
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Construct a polynomial function that might have the given graph. (Use the smallest degree possible.)
3.1.77 Which of the following is a polynomial function that might have the given graph! Construct...
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9. Which of the following polynomial functions might have the graph shown in the illustration? a. f(x) = x*(x-4)*(x+3) b. f(x) = x(x-4)(x+31° C. f(x) = x°[x+4)*(x-3) d. f(x) = x(x+4)(x-3) e. f(x) = x(x-4)(x+3) 10. Find all zeros, real and complex, of the function f(x) = 3x +7x' +14x+28x + 8. a. 6.-2.-21,21} b. 6 -2,-2,2} C. (-3,-2 -21, 21) d. 6.2.-21, 21} e. (-3,-2, -2,2) 11. In the problem, t is a real number and...
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Q2 4 Points For questions 2.1 and 2.2, find and graph a polynomial function with the given zeros, multiplicities, and degree. (There are many correct answers.) Zero: -3, multiplicity: 1 Zero: 1, multiplicity: 3 Degree 4 Rises to the right Rises to the left Q2.1 2 Points Write the function definition. Leave your answer in factored form. You do not have to multiply it out. f(x) = (type your answer below or upload a picture) N Enter your answer here...