Solution-
If X ~ U (37, 84)
(Uniformily distributed between 37 and 84).
So, Probability density function is
f(X) = 1/(84-37) = 47
Now, the required probability is
P(X > 46| X < 71)
= P( 46< X < 71)/P(37 <X<71)
= [(71-46)/f(x)] / [(71-37)/f(x)]
= (71 -46)/(71-37)
= 25/34
=0.735291176
≈0.7353
Hence, P(X>46 | X <71) = 0.7353
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