Given
22 out of 80 students have shopped online
p̂ = 22/80 = 0.275
Sample proportion
n = 80
Sample Size
p = 0.6
(60%) Population
(Hypothesized) proportion
α = 0.10
10% Level of
significance
a) The null and alternative hypothesis are
Ho : p = 0.60
H1 : p < 0.60
This is a left tail test
b) We use the z-distribution for
calculating the test statistic which is a normal
distribution
c) For α = 0.10, we find the z-critical for the left
tailed test using standard Normal Tables or Excel function
NORM.S.INV
z-critical = NORM.S.INV(0.05)
z-critical = -1.645
Rejection Criteria
Reject Ho if calculated test statistic z <
-1.645
Graph of the test statistic, critical point and
rejection region
d) We use the z-distribution for calculating the test
statistic which is a normal distribution
We find z, the test statistic as
where
Test Statistic z = -5.934
Test statistic on the graph
-5.934 < -1.645
That is, Test statistic z < Critical z
Hence, we Reject Ho
e) Conclusion :
There exists sufficient statistical evidence
to conclude that
true population proportion is lower than
60%
--------------------------------------------------------------------------------------------------------------------
If you are satisfied with the solution, kindly give a thumbs
up.
a random sample of 80 graduate students 1 (6 points). A random sample of 80 graduate...
12.) A research company claims that 60% or more graduate students have bought online merchandise. A consumer group is sus of the claim and thinks that the proportion is lower than 60%. A random sample of 80 graduate students show that only 22 students have ever done so. Is there enough evidence to show that the true proportion is lower than 60%? Conduct the test at 10% Type I error rate, and use the p-value and rejection region approaches.
An e-commerce research company claims that 60% or more graduate students have bought merchandise on-line. A consumer group is suspicious of the claim and thinks that the proportion is lower than 60%. A random sample of 80 graduate students show that only 22 students have ever done so. Is there enough evidence to show that the true proportion is lower than 60%? Conduct the test at 10% Type I error rate, and use both p-value and rejection region approaches. **Make...
The Washington Post reported that 80% of all high school students had computers at their home. A random sample of 500 high school students in an urban area is taken, and it reveals that 425 students have computers at home. Test if the proportion of high school students in this urban area who have computers at their home exceeds 80%. Use a 0.1 level of significance. Part A: State the null and alternative hypotheses. a. H0: p = 0.8, Ha:...
An education researcher claims that 54% of college students work year-round. In a random sample of 200 college students, 108 say they work year-round. At a = 0.01, is there enough evidence to reject the researcher's claim? Complete parts (a) through (e) below. (a) Identify the claim and state Ho and Ha Identify the claim in this scenario. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do...
3. At CSUF, a simple random sample of 100 entering graduate students in 2018 found that 20 of the sampled students in the bottom third of their undergraduate class. Admission standards were tightened in 2019. In 2019, a simple random sample of 100 entering graduate students found that only 10 finished bottom third of their undergraduate class. Let P, and p, be the proportions of all entering graduate students in 2018 and 2019, respectively, who graduated in the bottom third...
HELP A random sample of 10 college students was drawn fr om a large university. Their ages are 22, 17,27, 20, 23, 19,24, 18, 19, and 24 years, with a sample of 3.2. Suppose that you want to test whether the population mean age differs from 20 What is the rejection region for a hypothesis test at a 1% significance level? O right and left tail rejection regions beyond a t critical value of 2.821 in the left tail and...
You wish to test the following claim ( H a ) at a significance level of α = 0.002 . H o : p 1 = p 2 H a : p 1 > p 2 You obtain 45.2% successes in a sample of size n 1 = 217 from the first population. You obtain 33.3% successes in a sample of size n 2 = 727 from the second population. For this test, use the normal distribution as an approximation...
You wish to test the following claim ( H a ) at a significance level of α = 0.005 . H o : p 1 = p 2 H a : p 1 < p 2 You obtain 11.3% successes in a sample of size n 1 = 781 from the first population. You obtain 14.2% successes in a sample of size n 2 = 639 from the second population. For this test, use the normal distribution as an approximation...
At a certain college a random sample of 90 college students were surveyed and 75 students were found to have cars on campus. It had long been believed that 80% of students kept their cars on campus. Is there evidence, using alpha = 0.05, to say the proportion has increased? State the type of test you are performing (multiple choice) State the null and alternative hypotheses Using Minitab results, state the test statistic Using Minitab results, state the p-value Decision...
You wish to test the following claim ( H a ) at a significance level of α = 0.05 . H o : p 1 = p 2 H a : p 1 ≠ p 2 You obtain 63.1% successes in a sample of size n 1 = 203 from the first population. You obtain 80.9% successes in a sample of size n 2 = 230 from the second population. For this test, you should NOT use the continuity correction,...