Question

Consider the value of t such that 0.05 of the area under the curve is to the left of 1. Step 2 of 2: Assuming the degrees of freedom equals 15. select the value from the I table. Answer E Tables Keypad Keyboard Shortcuts To select a value from the table either click the cell at the intersection of the row and column or use the arrow keys to find the appropriate cell in the table and select it using the Space key. To change the sign of the selected value, use the +/- button. +/- DF 1 2 3 4 0.1 0.05 0.025 0.01 0.005 3.078 6.314 12.706 31.821 63.657 1.886 2.920 4.303 6.965 9.925 1.638 2.353 3.182 4.541 5.841 1.533 2.132 2.776 3.747 4.604 1.476 2.015 2.571 3.365 4.032 1.440 1.943 2.447 3.143 3.707 1.415 1.895 2.365 2.998 3.499 1.397 1.860 2.306 2.896 3.355 1900 5 6 7 8 ריח ר תחרר Submit Answer 2020 Hawkes Learning

Answer 1

we have to calculate value to such that p(t<tc)=0.05 where thas is degrees of freedom from t table for p=0.05, degrees of freedom is we have value 1:753 but t table gives upper tail probability le pl t>1.753) =0:05 it distribution is symmetric p(t > )=P(t <-9) : Pitsto Plt ?):753) = 0.05 comparing ① and @ te= -1.753 for is degrees of breed om 6.05 0:05 WWW -t=1.753 te-1.753