Students investigating the packaging of potato chips purchased 0 bags of chips marked with a net...
Students investigating the packaging of potato chips purchased 6 bags of chips marked with a net weight of 29.4 grams. They carefully weighed the contents of each bag, recording the following weights (in grams): 29.2 , 28.4 , 29.3 , 28.6 , 28.7 , 28.7 . Find the mean and standard deviation of the weights.
Students investigating the packaging of potato chips purchased 6 bags of Lay's Ruffles marked with a net weight of 28.3 grams. They carefully weighed the contents of each bag, recording the following weights (in grams) 29.3 28.2 29.1 28.7 28.9 28.5 a) What is the mean weight? b) What is the standard deviation of the weights? (Need help? Here is @ the Routput) [+].) c) What is the Z-score for the minimum weight? d) What is the Z-score for the...
6. (from Q32 P. 594) Some students checked 6 bags of Doritos marked with a net weight of 28.3 grams. They carefully weighed the contents of each bag, recording the following weights (in grams): 29.2, 28.5, 28.7, 28.9, 29.1, 29.5 a. (1 mark) Calculate the sample incall, aud its standard error s/vn. b. (2 marks) Create a 95% confidence interval for the mean weight of such bags. c. (3 marks) State Ho and Ha and calculate a p-value if we...
As a project for an Introductory Statistics course, students checked 6 bags of Fritos marked with a net weight of 35.4 grams. They carefully weighed the contents of each bag, recording the following weights (in grams): 35.5, 35.3, 35.1, 36.4, 35.4, 35.5. Is there evidence that the mean weight of bags of Fritos is less than advertised? a) write the appropriate hypotheses b) do these data satisfy the assumptions for inference? Explain. c) test your hypothesis using all 6 weights...
Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. If we were to conduct a test to see if the sample estimate is different...
19: Bags of a certain brand of tortilla chips claim to have a net weight of 14 oz. Net weights actually vary slightly from bag to bag and are normally distributed with mean µ. A representative of a consumer advocate group wishes to see if there is any evidence that the mean net weight is less than advertised and so intends to test the hypotheses Ho: µ = 14, Ho: µ < 14. To do this, he selects 25 bags...
Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s= .80 n = 18. If we were to conduct a test to see if the sample estimate is different from...
Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. 18 mean 20.45 s = .80 n = If we were to conduct a test to see if the sample estimate is different from...
Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. If we were to conduct a test to see if the sample estimate is different...
Question 14 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s=.80 n = 18. A 95% confidence interval would have what as the Bound of Error? 20.052...