Degrees of freedom = 18 - 1 = 17
Alpha level = 0.05
This is a two tailed test. Hence,
Critical t values = -2.110, 2.110
Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack...
Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. If we were to conduct a test to see if the sample estimate is different...
Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. 18 mean 20.45 s = .80 n = If we were to conduct a test to see if the sample estimate is different from...
Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. If we were to conduct a test to see if the sample estimate is different...
Question 14 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s=.80 n = 18. A 95% confidence interval would have what as the Bound of Error? 20.052...
Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of a shift 15 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 15 bags yielded the following data. mean = 19.45 s = .64 n = 15. A 90% confidence interval would have what as the lower and upper bounds?
Question 14 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s=.80 n = 18. If we were to conduct a test to see if the sample estimate...
Question 13 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. A 95% confidence interval would have what as the Bound of...
Question 15 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of a shift 15 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 15 bags yielded the following data. mean 19.45 s= .64 n 15 A 90% confidence interval would have what as the Bound of Error? 19.159 to...
Question 14 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. If we were to conduct a test to see if the...
Question 17 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of a shift 15 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 15 bags yielded the following data. mean - 19.45 s - .64 n = 15. Based on a BOE-.354 for a 95% Confidence Interval for the...