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If y = f(x), the inverse of f is given by Lagranges identity: 1 dn-1 f-1(y) = = y + n! dyn–ī [y – f(y)] when this series co

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If- (Y) = y + fy- f(y)] ☺ Given data gf (y = f(x) Then d lagrangnges dentity + el te n! dyn- Given. verify lag anges ident3 Given dala ii) show that one root of the eq; *-*ckis x=Ž gent (3n)! in! (2n+1)! 430+1 To find sum of the series x=3 (n)!

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