8-9r 7-8x (1 point) Find the inverse function to y = (x) = . x=f-1(y) =...
8x +3 7x + 8 Find the inverse of the function f(x) I =
8 7. (1 point) Find the inverse Laplace transform f(t) = C-' (F(s)) of the function F(s) = $-2 10=c='{, *2 -3} - help (formulas)
how to solve this? The function f is one-to-one. Find its inverse. f(x) = 8x² +9, x20 O A f'(X) = 8 √x-9 X20 B. f'(x) = X-9 8 X29 c. f-'(x) = 8 X-9 X>9 Ix-9 OD. F"(x) = - 8,x29
(1 point) Find the inverse Laplace transform f(t) = 2" (F(s)} of the function F(s) = 2s 8²-1 (t) = -1 ^{}--G-- help (formulas)
Find the derivative of the function. f(x) = arccsc 8x -1 f'(x) = x\V 16x2 – 1 10 ny Find an equation of the tangent line to the graph of the function at the given point. y = - arccos y 37 2 xt. = - arccOS X
Find the inverse, f-1(x), for each function 7. f(x) x3 2х+3 8. f (x) 5x4
(1 point) Find the Inverse Laplace transform f(t) = --! {F(s)) of the function F(s) 120 120 f(t) = -1 help (formulas)
Let ?(?)=?2−8?+4f(x)=x2−8x+4. (1 point) Let f(x) = x2 – 8x + 4. Find the critical point c of f(x) and compute f(c). The critical point c is = The value of f(c) = Compute the value of f(x) at the endpoints of the interval [0, 8]. f(0) = f(8) = Determine the min and max Minimum value = Maximum value = Find the extreme values of f(x) on [0, 1]. Minimum value = Maximum value =
3 (1 point) Find the inverse Laplace transform f(t) = --! {F(s)} of the function F(s) = - 25 32 +25 $2 + 16 f(t) = -1 e='{-6816+,725)} = help (formulas)
(1 point) Consider the function f(x, y) = e-8x=x2-4y—y2 Find and classify all critical points of the function. If there are more blanks than critical points, leave the remaining entries blank. fx = fxx = fxy =