Find L{ e3t(1 - 2t + 5sin2t)}. 2 1 9-3 + 5(3-3) (3-3)² +4 (3-3)² O...
Question 9 3 pts The Laplace transform of the piecewise continuous function J4, 0< < 3 f(t) is given by 2, t> 3 2 L{f} (2 - e-st), 8 >0. S L{f} (1 – 3e-), 8>0. 8 2 L{f} (3 - e-s), 8 >0. S L{f} = (1 – 2e-st), s > 0. None of them Question 10 3 pts yll - 4y = 16 cos 2t To find the solution of the Initial-Value Problem y(0) = 0 the y...
QUESTION 4 One solution of x' = The general solution is 1 2 e3t ОА. + C3 e3t Int x+b(e) is x(e) = [7] 0 [8]+ole [l] to (o) ( OB + Ci Int] et + e3t OD ci Int OC e3t Ci + C2 + C3 Int
QUESTION 4 One solution of x' = The general solution is 1 2 e3t ОА. + C3 e3t Int x+b(e) is x(e) = [7] 0 [8]+ole [l] to (o) ( OB + Ci Int] et + e3t OD ci Int OC e3t Ci + C2 + C3 Int
2. Let t if 5 < t < 10 f(t) = -{ e3t if t > 10 Use the Heaviside step function to evaluate the Laplace of f. (4 pts.) 3. Find the inverse Laplace transform of the following functions: (i) F(s) = 4s +5 s(s2 + 4s + 5) (3 pts.) -35 (ii) G(s) = 4s + 5 s(s2 + 4s + 5) е (you may use part (i)) (2 pts.)
Find the Inverse Transform L {F(s)} of F(s) 38+2 $2 -38 +2 o L 1{F(s)} = 8e2t - 5et OL-'{F(s)} 5 8-1 $ 2 L'{F(s)} = -5e2-8et None of them
Find f. f'(t) = 2t - 4 sint, (0)= 5 Select one: a. f(t) = 2t - 3 sint +5 O b. f(t)= +2 +4 cost +1 c. f(t)=12 - 3 cost-5 d. f(t) = x2 +3 cost e. None of these
find L^-1 {4s/s^2 + 2s -3} 4s Find L s2 + 25 - 3 5 -3t (write 5/6 by 6' , e^{-3t} bye and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
find L^-1 {2s+4 / s(s^2+4)} 2s+4 Find L s(s2+4) 5 -30 (write 576 by 6 e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t).
4) Do the lines: L: x = 2t + 3, y = 3t – 2, z = 4t - 1 and L2 : x = 8 +6, y = 2s + 2, z = 2s + 5 intersect? If not provide a reason, if yes find the intersection point.
Select the correct statement. 3e-8 52 + 9 *} sin(3t) *e! O N {}={2- t <3 3 t > 3 O None of the other options о {*} = 6(e – 2)51 OL-{L {** f(t)}} = f(") (t) Select the correct statement. of{e * sin(2) +e*t} - 2+2+5 8 (-3) None of the other options O L {eztult - 3)} = e-3 L {e2(t-"}} w O (t + 1)2 5 (t-1) 5 x{05e-1) + at -1)}- di (-4e")+eos ${sin(t –...