Question 1 :- answer ) =>Option (ii)
Question 2 :- answer => option (i)
Select the correct statement. 3e-8 52 + 9 *} sin(3t) *e! O N {}={2- t <3...
8 Determine L-1 { (8+3)2 O None of them O e-3t + te -3t e-3t 3te-30 O e-3t - 3e-3t
1.) 2.) 3.) Identify f(t) for the function F(s) 8(+ 2)(8 + 3) s(s + 2)(s + 4) Multiple Choice (3.00+ 2.00e-2t-3.00e-4540 4.00u(t+ 2.00e-2t+3.00e-4t O (3.00 + 2.00e-2t +3.00e-44 3.00u(t) +2.00 e e-2t+4.00e-4 Find f(t) for the function F(s) = 32- 8s + 4 (s + 1)(8 + 2)2 Multiple Choice O 29=-24e-t+ (-12) -2t *+(-24)te-27 О = (13e-t +(-12)e-2t + (-24)te-21) (1) + O 10 = (13e-*+(-24)e-2 +(-12)te-210 80 = 8e-T+(-12)e-2t + (-24)te-2t Identify f(t) for the function F...
1. Find the Laplace transform of the function f(t) = 1 + 2t + 3e-3t - 5 sin(4t). Solution: 2. Find the inverse Laplace transform of F(s) = 7+ (8 + 4)(18 - 3s) (s - 3)(s – 1)(s + 4)" Solution:
Q1) Find the Laplace Transform of the following functions: 1. e +5 2. cos(2t)+7sin(2) 3t)+sin(3) 4. 10+ 5t +12-4 5. (+2)e 6. Gcos(21)-
e-27 2. Calculate L et sint+e-2t cos st sint+e-2 cos 3t+t%e3+ + ✓at ec [e*sin U2n(t) sin 2t sin 21
(3e-4 -8t +9 Consider the vector-valued functions xi(t) = | (-2+2 + 3t) and 22(t) = 3e-4t a. Compute the Wronskian of these two vectors. Wx(t) = (67 – 33t+27)e-4t), b. On which intervals are the vectors linearly independent? If there is more than one interval, enter a comma-separated list of intervals. The vectors are linearly independent on the interval(s): (-infinity,1),(1,4.5),(4.5, infinity), help (intervals). c. Find a matrix P(t) = (Pu(t) P12(t)) so that 21 and 22 are fundamental solutions...
QUESTION 12 Apply Laplace Inverse to find f(t): s +7 F(s) = 5(52 + 4s +3) Choose the correct answer: L-'[F(s)] = f() 1) f(1) = 4t’e-31 - 3e-+ + 7t 2) f(t) = 5t? - 3e-4 3) f(0) =2-31 - 3e-- + 4) f() = 6e-6 - e-31 +} QUESTION 13 Solve the ODE: 2 2 + 3ź - 2z = te-2 z(0) = 0 & ż(0) = -2 Choose the correct answer: 1) z(t) = -0.768 0.5t -...
1.) 2.) Find f(t) for the function F(s) = 52 - 8s + 4 (s + 1)(8 + 2)2 Multiple Choice O =-24e-t+ + (-12)e-2t+6 +(-24)te-27 O 19 = (13e-++(-12)e-2t +(-24)te-210 O p0 = (13e-+ +(-24)e-2t+ (-12)te-24) (0) O 10 = 8e-t +(-12)e-2t *+ (-24)te-27 Identify f(t) for the function F (s) = 32 + 1 (s+3)(s2+4s+5) Multiple Choice 5e-3t_4e-2 tsin(t) О (5e-3t_4e-2tcos(f)( (5e-3t+4e-2tcos() 4e-36-5e-2tcos()
6. Mix and match. You may also answer "none of these" F(s) = L{ft) f(t)= {F($)} 4 – 36 – 4e 35+3 s-(S-1) та 3s +3 $2(52 -1) - 4+7t + 4e7 -6-3t + 6e -7s+3 s-(s -1) 7s+7 $2(2-1) d -7-7t + Tet | 3s +7 s(s+1) le - 3 – 3t + 3e' 3s +7 $2(5+1) 3 - 3t - 3 cos t + 3 sint 4 + 70-4e | 3s - 7 s-(s-1) | 3s +7 s-(s-1)...
For a given law of motion of a particle M find a location of a particle for a time ty (in sec), trajectory, velocuty, tangential, normal and full acceleration -2t +3 4 cos (xt/3) 2 4 sin2(xt/3) sin(rt/3) -1 4t +4 2sin(t/3) 3e2 +2 3t2 + 7 sin(rt/6) +3 -3cos(nt/3) + 4 -141 1/2 2os(t/6) 4 cos(t/3) 10 83t 5 cos (t/6)-3 -5 sin rt2/3) 1/2 5 sin2(xt/6) 5 cos(rt2/3) -2t-2 412 13 14 4 cos(xt/3) 3sin(rt/3) 16 3t 1/2...