Q1) Find the Laplace Transform of the following functions: 1. e +5 2. cos(2t)+7sin(2) 3t)+sin(3) 4....
2. Find the Laplace transform of the following functions (a) f(t)3t+4 (b) cos(2Tt) (c) sin(2t T) (d) sin(t) cos(t) "Use Trig. Identity" (e) f(t) te 2t use first shifting theorem
Find Laplace Transform for the following functions: 5- f(t) = 3t^e2t 6- f(t) = e-+(2+* + 3t2 +10) 7- f(t) = e-4 cos(3) Find Laplace inverse: 5- F(s) 2 2+9 6- F(S) = (s+3)* 7- F($) = (s+1)(8-2) 10 8- F(s) = (3-3)(s+4) 9. F(S) s(s-1)(3-4) 35+1
QUESTION 3 After use Laplace Transform to transform the following initial value problem X" +x=e-t, x(0) = 1,x'(0) = 1, S-2 you should get X(s)= (write fraction as (S-2)/(5-4)(8+6) for -). Then, find (s-4)(8+6) x(t)= L-?{X(s)}= (write 5/6 by 5 -30 6' e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
1. Find the Laplace transform of the function f(t) = 1 + 2t + 3e-3t - 5 sin(4t). Solution: 2. Find the inverse Laplace transform of F(s) = 7+ (8 + 4)(18 - 3s) (s - 3)(s – 1)(s + 4)" Solution:
Find L 2s+4 s(s2+4) 5 -3t (write 5/6 by 5 e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
The Laplace transform of the following time function f (t) = 2t2 + e-2t sin 3t is
(write After use Laplace Transform to transform the following initial value problem x" + 2x' +x=3, x(0)=0,x'(0)=1, you should get X(s)= S-2 fraction as (S-2)/(S-4)(8+6) for -). Then, find x(t) = £-2(x(s)= (s-4)(3+6) (write 5/6 by 5 -3t 6' , e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
Find the inverse Laplace transform of the function F(s) s +1 $2 - 8s + 20 * uz(t)e(4t-12) (cos(2t – 6) + 2.5 sin(2t – 6)) OF U3(t)e4t (cos(2t – 3) + 0.5 sin(2t – 3)) OC e(4t-12) (cos(2t – 3) + sin(2t – 3)) OD uz(t) (cos(2t – 6) + sin(2t – 6)) ОЕ uz(t) (e4t – 5t)
Calculate the Laplace transform of the following time functions by applying the Laplace transform properties: f) f(t) = 3t cos(t) g) f(t) = 3t sin(3t) h) f(t) = 2te*** – 3t sin(t) i) f(t) = t sin(3t) + 2t cos(t) j) f(t) = 5sin(t)/(3t)
QUESTION 1 use to following initial value problem (write fraction as After Laplace Transform transform the x" + 3x' + 2x=2e-t, x(0) = x'(0)=0, you should get X(s)= S-2 (S-2)/(5-4)(s+6) for (s-4)(s+6) -). Then, find x(t)= L-(x(s))= 5 -3t (write 5/6 by 6' ; e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).