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(1 point) -6 -3 Use Theorem 5.5.2 to write the vector v = -4 as linear combination of -3/V14 1/714 -2/V13 0/V13 -3/V182 -13/V

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-6 given V- -3/17 -3 14 -2119 ५ 43 -2013 0/13 3115 v= GM & Gų f z Uz 31/122 -13/1122 -21182 3-262 ल -353 Co 1182 33 (82 - -301 30 -15 923 V182 -282 3120 302 -10 (22 39) + 20) -132 12 4-65 C.S TE2 59 ( 423 182 NSS) (ऽ- 2730 182 52 1-जाप ( -3-13 (५

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