Question

Question 35 2 pts 35. In clinical trials of Nasonex, 3770 adult and adolescent allergy patients (patients 12 years and older) were randomly divided into two groups. The patients in group 1 (experimental group) received 200 ug of Nasonex, while the patients in group 2 (control group) received a placebo. Of the 2000 patients in the experimental group, 705 reported headaches as a side effect. Of the 1770 patients in the control group, 1390 reported headaches as a side effect. Is group 1 patients experience les than group 2? Use a=0.10. Answer questions 35 to 39. Write both alternative and null hypotheses. O H1: P1 - P2; HO: P1 <P2 Right tail test Ο Ο Ο O H1: P1 = P2; HO: P1 - P2 Two tail test O H1: P1 > P2; HO: P1 = P2 Right tail test O H1: P1 <P2; HO: P1 = P2 Left tail test Question 36 3 pts 36. Find test statistics (show formula and final answer with two decimals) O z= 2.32 O z= -2.69 O z= -22.69 O z= -26.69 Question 37 2 pts 37. Find P-value

Answer 1

35) Null and alternative hypothesis: 0 H:P=P H:P.<P2 The type of test is left tailed test Level of significance, a=0.10 Hence, the correct answer is option (4) H:P, <P2;H, : P2 = Pz;left tailed test Calculate test statistic and p-value using Excel (Mega stat): 1. Click on add ins > mega stat commands > hypothesis test > hypothesis test for two proportions. 2. In hypothesis test for two proportions dialog box, enter n and x values confidence level 90% > hypothesis difference as 0 > alternative as less than. 3. Click ok. Output:

Hypothesis test for two independent proportions p2 p1 ро 0.3525 0.7853 0.5557 p (as decimal) 705/2000 1390/1770 2095/3770 p (as fraction) 705 1390 2095. X 2000 1770 3770 n -0.4328 difference 0. hypothesized difference 0.0162 std. error -26.69 z 0.0000 p-value (one-tailed, lower) 36) In the output, the test statisticis z=-26.69 Hence, the correct answer is option (4) 37) The p-value is 0.0000 Decision rule: Reject Ho, if ps a otherwise do not reject H. Since the p-value is less than the level of significance, so we reject the null hypothesis at 10% significance level. Conclusion: There is sufficient evidence to support the claim that proportion of group 1 patients experience less than group 2