Question

9.1 question 10

Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 39 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 86 of the 99 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo What are the null and alternative hypotheses for the hypothesis test? A. Ho: P = P2 H: P1 P2 D. Ho: P = P2 H: P1 P2 OB. Ho: P1 P2 HP: "P2 O E. HOP SP2 HP1P2 OC. Ho: P1 = P2 HP <P2 OF HO: D12P2 H:P*P2 Identify the test statistic. Z (Round to two decimal places as needed.)

what is the p- value?

what is the confidence interval?

9.1 question 10 part 2

what is the p- value?

what is the confidence interval?

Answer 1

o Salution 8 = xl = 33. 22 = 86 h| 39 hz 99 0.01 claim. Echinacea has an effect on chinovirus infactions (a) to: P,=P2 Hii Pit P2 Option "A is correct answer = Test statistic Z=P,MP2 ph C1-p?) P2" (1-82"} ni 7 h2 Pin = 21 P2 242 33 ni = 0.84 39 86 N2 0.86 99 z = 0.84 -0.86 0.84(1-034) 39 0-86(1-0-86) t 99 22-029 IP-valle =0.772 CS Scanned with CamScanner

2 Conclusion - P-value is greater than the significance level of X=0.01, so we fail to greject the hull hypothesis . There is not or no sufficient evidance to support The claim that echinacea has an effect T997. Interval for Pi-P2 Zx/2 = 20.01 20:005 = 258 2 a) P, A P² +2.58 Pi^(1-P^) 't P2^C1-224) ny hz 0.84-0.867 2.58 0.84(1-0-84) 39 t 0.86(1-0.86) 99 -0.02 – 0.176 =) (-0.196,0:156) possible As per HomeworkLib policy i only upload one answer, I request to send another question. As ear early Thank 2 post the answer, you CS Scanned with CamScanner