Question

Find all points (if any) of horizontal and vertical tangency to the curve. Use a graphing utility to confirm your results. (O
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Answer #1

Here, we have to take derivative of x and y

dx/d\theta = -sin(\theta)

dy/d\theta = 4cos(2\theta)

So,

dy/dx = -4cos(2\theta) /sin(\theta)

When this goes to zero, there will be a horizontal asymptote.

This happens when

cos(2\theta) = 0

\theta) = \pi/4, 3pi/4, 5\pi/4...

This will correspond to

(x, y) = (1/\sqrt 2,2), (-1/\sqrt 2,-2),(-1/\sqrt 2,2),(1/\sqrt 2,-2),The vertical asymtote happens when dy/dt is not equal to zero, and dx/dt = 0

This happens at

\theta = 0,\pi,2\pi...

So,

(x, y) = (1, 0), (-1, 0)

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