A survey found that 60% of American victims of health care fraud are senior citizens. If...
A survey found that 60% of American victims of health care fraud are senior citizens. If 10 victims are selected at random, find
(A) the mean number of victims who are senior citizens.
(B) the probability that exactly 3 victims are senior citizens.
(C) the probability that at most 6 victims are senior citizens.
(D) the probability that all but one victim are senior citizens.
in words, what is the success and failure part of this binomial problem?
also can you help me figure out the p, q, mean and standard deviation. thank you
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A survey found that 60% of American victims of health care fraud
are senior citizens. If...
A survey found that 60% of American victims of health care fraud are senior citizens. If...
A survey found that 60% of American victims of health care fraud are senior citizens. If 10 victims are selected at random, find (A) the mean number of victims who are senior citizens. ( C) the probability that at most 6 victims are senior citizens. (D) the probability that all but one victim are senior citizens. D is the one I need most help in, I have gotten the answer "0.0016" "0.0403" and "0.999895" im very confused with it. also...
A survey found that 60% of American victims of health care fraud are senior citizens. If...
A survey found that 60% of American victims of health care fraud are senior citizens. If 10 victims are selected at random, find (A) the mean number of victims who are senior citizens. (C) the probability that at most 6 victims are senior citizens. (D) the probability that all but one victim are senior citizens. D is the one I need most help in, I have gotten the answer "0.0016" "0.0403" and "0.999895" im very confused with it. Also can...
A survey found that 60% of American victims of health care fraud are senior citizens. If...
A survey found that 60% of American victims of health care fraud are senior citizens. If 10 victims are selected at random, find (A) the mean number of victims who are senior citizens. (B) the probability that exactly 3 victims are senior citizens. (C) the probability that at most 6 victims are senior citizens. (D) the probability that all but one victim are senior citizens. I only need help with A,C, and D. I know that B is 0.0425. If...
A survey found that 60% of American victims of health care fraud are senior citizens. If...
A survey found that 60% of American victims of health care fraud are senior citizens. If 10 victims are selected at random, find (A) the mean number of victims who are senior citizens. (B) the probability that exactly 3 victims are senior citizens. (C) the probability that at most 6 victims are senior citizens. (D) the probability that all but one victim are senior citizens.
it was found that 80 percent of americans victims of healthcare fraud are senior citizens. if...
it was found that 80 percent of americans victims of healthcare fraud are senior citizens. if 9 victims are randomly selected, find the probability that 5 are senior citizens. round your answers to three decimal places. P(exactly 5)=
26. A large survey found that an American family generates an average of 17.6 lb of...
26. A large survey found that an American family generates an average of 17.6 lb of glass garbage each year. Assume normal distribution with the standard deviation of 3.5 pounds. a. What proportion of families generates less than 17 lbs of glass garbage each year? b. If a family is selected at random, what is the probability that it generated less than 17 lbs of glass garbage in a year? c. If a sample of 35 families is randomly selected,...
(1) A survey found that the American family generates an average of 17.2 pounds of glass...
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