Question

A survey found that 60% of American victims of health care fraud are senior citizens. If 10 victims are selected at random, find

(A) the mean number of victims who are senior citizens.

(B) the probability that exactly 3 victims are senior citizens.

(C) the probability that at most 6 victims are senior citizens.

(D) the probability that all but one victim are senior citizens.

Answer 1

2.] hore Xi victims of health care brand 0.60 P = boy. n=10 X N Binomial (h. 10, p=0.6) then pdf is & P(x) = he pee (1-pin-ne H = 0, 1, 2, o.w. Al find find meen number of vichin we have to find Elx) mean of binomial is no . Elxlan np Toyo6 -16 6 Answer: 6

B probability that exactly 3 victions - P(X=3) = nose pre 21-on-1 0,0 42 467328 a 10,042467 Answer! 0,042 967 c) probability of at most o victims P(x<6) = 1-P(X>6) = 1 - [pix) PIX-8) +Px=9). +P(x=10)] 0,214990848 +0./20932352 +0.0401078440.0060466177 - - 0.382 2 80601 0.617219399 0.617719 Answer: 0,617719

o probability that all but one victim mean, probability of at least one victim ::P(X), 1) = 1-P(x (4) - 1-plyzo) = 1- 10. (0-6)(0.4) = 1-10.400 - 0.999895142 M 10.999895 Answer: O.ggg 895