Question

This Test: 20 DIS POSLO 20 of 20 (14 complete This Question: 1 pt o The average healing time of a certain type of incision is 192 hours, with standard deviation of 30 hours. What percentage of the people having this incision would heal in 7 days or less? Assume a normal distribution mm Click the icon to view the area under the standard normal curve table 0.00% of people having this incision should heal in 7 days or less. Type an integer or decimal rounded to the nearest hundredth as needed) ind Llon w 7 On Enter your answer in the newer box this earning G Search or type URL D Q + 3 % 5 & 7 8 0 9 2 6 4 P O Р W E R T U Y H L J G F к S L

Answer 1

Solution 30 Given data Mean (4) 192 Stan dard deviation (5) - We have to find the percentage of the people having this incision Would heal heal in We know that I day 24 hours Number of hours in af days = 7x24 I days ar less 168 hours Now X-M z = o=30 in X=168, M= 192 and We have to substitute equation then we get 168 - 192 Z 30 -24 z = 30 Z=-0.8 table area from to left of oos is 0.7881 By using Now the 0.8 = 0.7881 - 0.5 area O and between = 0.2881

'We know that 2 Area Under standard normal curve from o to - ais equal to a area from o to So area o and 0.8 0.2881 Now p(xs168) = Agree to left of -0.8 = 0.5 -0.2881 0.2119 P(Xc168) = 191.196%. 21.19% of people having this incision should heal in 7 days or less