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Question 1 of 1 - / 1 View Policies Current Attempt in Progress The mean breaking strength of a ceramic insulator must be at
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Answer #1

Solution:

Given:

From the data, sample mean is r = 9.20 and the Sample standard deviation is s = 0.21

The sample size is n = 50.

a) Null and Alternative Hypotheses:

Η : μ29.4 Η :μ<9.4

This corresponds to a left-tail test, for which a t-test for one mean, with unknown population standard deviation will be used.

Test statistic:

1596248209293_image.png

The number of degrees of freedom are df = n-1 = 50-1 = 49

Rejection Region:
Given significance level = α = 0.05 and df = 49
So Critical Value for the test is, tc = -1.677   …Using excel formula, =TINV(2*(1-0.05),49)

Decision:

Since it is observed that |t| = 6.734> |tc| = 1.677
It is then concluded that the Null Hypothesis is rejected.

b) Conclusion: There is not enough evidence to conclude that the process by which the insulator are manufactured is equivalent to the standard.

Done

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