Question

QUESTION 9 1 points Save Answer Past experience has indicated that the breaking strength of yarn used in manufacturing draper

0 0
Add a comment Improve this question Transcribed image text
Answer #1

9) Z for 95% confidence interval = Z0.025 = 1.96

A =X- ー20.025 *

   6.2 = 19.7-1.96 *

   = 15.649 (ans)

10) sd = sqrt(25) = 5

Standard deviation of sampling distirbution= sd / sqrt(n)

or, 1.5 = 5 / sqrt(n)

or, n = 12 (ans)

Add a comment
Know the answer?
Add Answer to:
QUESTION 9 1 points Save Answer Past experience has indicated that the breaking strength of yarn...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is...

    Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed and that σ = 7.2 psi. A random sample of nine specimens is tested, and the average breaking strength is found to be 95.5 psi. The 95% confidence interval for the true mean breaking strength is written as (A ; B). Find the value of B? round your answer to three digits.

  • Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is...

    Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed and that o = 2 psi. A random sample of 8 specimens is tested, and the average breaking strength is found to be 97 psi. Find a 95% two-sided confidence interval on the true mean breaking strength. Round the answers to 1 decimal place. Sus

  • Question 7 The mean breaking strength of yarn used in manufacturing drapery material is required to...

    Question 7 The mean breaking strength of yarn used in manufacturing drapery material is required to be more than 100 psi. Past experience has indicated that the standard deviation of breaking strength is 2.9 psi. A random sample of 9 specimens is tested, and the average breaking strength is found to be 100.6 psi. Statistical Tables and Charts (a) Calculate the P-value. Round your answer to 3 decimal places (e.g. 98.765). If a = 0.05, should the fiber be judged...

  • Multiple Choice Question Previous experience has shown that the breaking strength of the fabric used in...

    Multiple Choice Question Previous experience has shown that the breaking strength of the fabric used in a certain brand of drapes is normally distributed with a standard deviation of 2 pounds per square inch. A random sample of 9 specimens is examined to reveal an average breaking strength of 98 pounds per square inch. Determine the p-value required to test the hypothesis that the true mean exceeds 97. - A. 0.067 B. 0.012 C. 0.13 D. 0.006 E. none of...

  • 4. Multiple Choice Question Previous experience has shown that the breaking strength of the fabric used...

    4. Multiple Choice Question Previous experience has shown that the breaking strength of the fabric used in a certain brand of drapes is normally distributed with with a mean of 97 pounds per square inch. A random sample of 9 specimens is examined to reveal an average breaking strength of 7 = 98 pounds per square inch and a standard deviation of 2 pounds per square inch are observed. The p-value to test the hypothesis that the true mean is...

  • Previous experience has shown that the breaking strength of the fabric used in a certain brand...

    Previous experience has shown that the breaking strength of the fabric used in a certain brand of drapes is normally distributed with a standard deviation of 2 pounds per square inch. A random sample of 25 specimens is examined to reveal an average breaking strength of a 98 pounds per square inch. Determine the p-value required to test the hypothesis that the true mean is not 97 A. 0.067 B. 0.012 C. 0.13 D. 0.006 E. none of the preceding

  • Previous experience has shown that the breaking strength of the fabric used in a certain brand...

    Previous experience has shown that the breaking strength of the fabric used in a certain brand of drapes is normally distributed with a standard deviation of 2 pounds per square inch. A random sample of 25 specimens is examined to reveal an average breaking strength of 1 = 98 pounds per square inch. Determine the p-value required to test the hypothesis that the true mean is not 97. A. 0.067 B. 0.012 C. 0.13 D. 0.006 E. none of the...

  • Question 1 of 1 - / 1 View Policies Current Attempt in Progress The mean breaking...

    Question 1 of 1 - / 1 View Policies Current Attempt in Progress The mean breaking strength of a ceramic insulator must be at least 10 psi. The process by which this insulator is manufactured must show equivalence to this standard. If the process can manufacture insulators with a mean breaking strength of at least 94 psl, it will be considered equivalent to the standard. A random sample of 50 insulators is available, and the sample mean and standard deviation...

  • Question 4 of 4 (1 point) The average breaking strength of a certain brand of steel...

    Question 4 of 4 (1 point) The average breaking strength of a certain brand of steel cable is 2000 pounds, with a standard deviation of 100 pounds. A sample of 20 cables is selected and tested. Find the sample mean that will cut off the upper 80% of all samples of size 20 taken from the population. Assume the variable is normally distributed. Round intermediatez-value calculations to 2 decimal places and round the final answer to 2 decimal places 6.3...

  • QUESTION 4 A new type of rope has a mean breaking strength of 25 kilograms with...

    QUESTION 4 A new type of rope has a mean breaking strength of 25 kilograms with a standard deviation of 3 kilogram. To test the hypothesis, a random sample of 50 lines are tested and the average breaking strength is found to be 22 kilograms. (a) Test the hypothesis, at the 0.05 level of significane the the mean is that u = 25 kilograms against the alternative that u < 25 kilograms. (b) Evaluate the P value of the test.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT