Question

The following table shows the weights (in pounds) and the number of hours slept in a day by a random sample of infants. Test the claim that M+0. Use a =0.01. Then interpret the results in the context of the problem. If convenient, use technology to solve the problem Click the icon to view more information about hypothesis testing for slope. Weight, 8.1 102 9.8 72 6.9 112 10.9 14.90 Hours slept, y 14.8 14.6 14.1 14.3 13.8 13.1 13.9 12.5 Identify the null and alternative hypotheses. O A. Ho: MSO HA:M0 O C. Ho M =0 HAM#0 OB. Ho: M70 HAM=0 OD. Ho: M20 HAM+0 Calculate the test statistic t= (Round to three decimal places as needed.) Calculate the P-value Click to select your answer(s).

Answer 1

leti x = weight, V = Hours slept. know that correlation coefficient (8) = 9gay Essai ssassy where, ssay [(xi-) (Yi-Y) Ssx = {( xi-x)², ssy = [(yi -ý)? Here, n=8 Eai= 7203 [yi= llll x= Exi 72.3 - 9.038 8 Ý Zui 11.1 130888 (xi - ☆ ) l Yi-Y) - 6.855 0.828 0.879 1.351 0.581 3.376 0.833 6.508 0.045 o.170 0.008 0162 -0.758 Oo 791 -1.703 81.675 4.676 0-620 0.023 3. 469 34. 369 Total 130.379 8. 134 1.925 yolog -90646 Here, ssay 9.640, SS&= 100 379, ssy = 4.10g. CS

.:8= -9.640 130.371x4.109 ng -0.4168 claim! Mto The null and alternative hypotheses, Anso © vs Homeo HAIR to Test statistic tcal 3 n-2 Ntn-z under Ho 1-82 = -0.4168 1-60.4168)3 tcay 1.1232 tcal = t = -10 123 p.value pCts -1:123) + PCty 1.123) 3 pct? 1.4123) + Plt) 1.123) (: t-disth is symmetric) = 2 pct > 1.123) p-value= 2 x 0 1521 p-value= 0.3043 Ans. P = 0.3043 CS

Herse, significance level 1d): 0.0) we reject Ho at 2 % level of signiticonce p-volue Ka (1.0.3) Here, p-vawe ya 0.30437 0.0 fail to reject Ho at 10% significance level. we conclusion:- fail to reject Ho. There is not sufficient evidence at the 1000 level of significance to support the claim that there is a linear pelationship between weight and no of hours nept CS sunt with ComSerials