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Question 4 3 pts In a previous study of body temperatures of 106 adults at midnight, with a range from 96.5°F to 99.6°F. Find
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Answer #1

Given : Margin of error=E=0.08

Significance level=\alpha=0.04

Now , the critical value is , Z_{\alpha/2}=Z_{0.04/2}=2.05 ; From Z-table

A. Now , the range is given by ,

Range = Largest observation - Smallest observation = 99.6-96.5=3.1

By using range rule of thumb , the standard deviation is ,

\sigma=\frac{Range}{4}=\frac{3.1}{4}=0.7750

Therefore , the required sample size is ,

n=(\frac{Z_{\alpha/2}*\sigma}{E})^2=(\frac{2.05*0.7750}{0.08})^2\approx 394

B. Since , \sigma=0.65

Therefore , the required sample size is ,

n=(\frac{Z_{\alpha/2}*\sigma}{E})^2=(\frac{2.05*0.65}{0.08})^2\approx 277

C.

i. Part (A) results will likely be better.

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