A particular fruit's weights are normally distributed, with a
mean of 784 grams and a standard deviation of 10 grams. The
heaviest 17% of fruits weigh more than how many grams?
Give your answer to the nearest gram.
Solution :
Given that,
mean = = 784
standard deviation = = 10
Using standard normal table ,
P(Z > z) = 17%
1 - P(Z < z) = 0.17
P(Z < z) = 1 - 0.17 = 0.83
P(Z < 0.95) = 0.83
z = 0.95
Using z-score formula,
x = z * +
x = 0.95 * 10 + 784 = 794
The heaviest 17% of fruits weigh more than is 794 grams
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