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ASK YOUR TEACHER An investigation was carried out to study the relationship between speed (ft/sec) and striderate number of s
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Answer #1

a) if x = speed and y = rate

Ʃx = 205.2
Ʃy = 35.13
Ʃxy = 660.118
Ʃx² = 3881.08
Ʃy² = 112.671
Sample size, n = 11
x̅ = Ʃx/n = 205.2/11 = 18.654545
y̅ = Ʃy/n = 35.13/11 = 3.1936364
SSxx = Ʃx² - (Ʃx)²/n = 3881.08 - (205.2)²/11 = 53.167273
SSyy = Ʃy² - (Ʃy)²/n = 112.671 - (35.13)²/11 = 0.4785545
SSxy = Ʃxy - (Ʃx)(Ʃy)/n = 660.118 - (205.2)(35.13)/11 = 4.7838182

Slope, b = SSxy/SSxx = 4.78382/53.16727 = 0.0899767

y-intercept, a = y̅ -b* x̅ = 3.19364 - (0.08998)*18.65455 = 1.5151611

Regression equation :

ŷ = (0.0900) x + 1.5152

b)

if x = rate and y = speed

Ʃx = 35.13
Ʃy = 205.2
Ʃxy = 660.118
Ʃx² = 112.671
Ʃy² = 3881.08
Sample size, n = 11
x̅ = Ʃx/n = 35.13/11 = 3.1936364
y̅ = Ʃy/n = 205.2/11 = 18.654545
SSxx = Ʃx² - (Ʃx)²/n = 112.671 - (35.13)²/11 = 0.4785545
SSyy = Ʃy² - (Ʃy)²/n = 3881.08 - (205.2)²/11 = 53.167273
SSxy = Ʃxy - (Ʃx)(Ʃy)/n = 660.118 - (35.13)(205.2)/11 = 4.7838182

Slope, b = SSxy/SSxx = 4.78382/0.47855 = 9.9963906

y-intercept, a = y̅ -b* x̅ = 18.65455 - (9.99639)*3.19364 = -13.270291

Regression equation :

ŷ = (9.9964) x -13.2703

c)

For part a) :

Coefficient of determination, r² = (SSxy)²/(SSxx*SSyy) = (4.78382)²/(53.16727*0.47855) = 0.899

For part b) :

Coefficient of determination, r² = (SSxy)²/(SSxx*SSyy) = (4.78382)²/(0.47855*53.16727) = 0.899

The Coefficient of determination for a) and b) are the same or very similar

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