Homework Answers
The number of degrees of freedom is df = (r-1)*(c-1) = (3-1)×(3-1) = 4
The significance level is α = 0.05
Critical Chi square value corresponding to α = 0.05 and df = 4 is obtained using chi square distrubtion table. Screenshot below:
Critical χ2 = 9.49
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QUESTION 8 Chi-Square (2 points) The contingency table below contains neighborhood-level homicide data broken down by...
QUESTION 9 Chi-Square The contingency table below contains neighborhood-level homicide data broken down by victim race....
QUESTION 9 Chi-Square The contingency table below contains neighborhood-level homicide data broken down by victim race. Using an a of .05, conduct a five-step hypothesis test to determine whether there is a relationship between neighborhood and victim race. Neighborhood Race Shenandoah Mahanoy North Schuylkill White 34 35 20 Black 12 Hispanic 8 3 0 Question: Do you reject the null hypothesis? 36 18 Yes ОО No
Cross-Tabulation and Chi-Square Test Respondents were asked to assess their current health condition and to report...
Cross-Tabulation and Chi-Square Test Respondents were asked to assess their current health condition and to report their social class. Data is in the table below Social Class Middle- and Upper Lower- and Working- Class Respondents Tetal Health Status Class Respondents Fair/Poor 220 136 Excellent/Good 472 521 Total 1. What is the independent variable? What is its level of measurement (nominal, ordinal, ratio)? What is the dependent variable? What is its level of measurement (nominal, ordinal, ratio)? 2. Use the frequencies...
1. These questions pertain to Table 1. a. How many chi-square tests of independence are performed?...
1. These questions pertain to Table 1.
a. How many chi-square tests of independence are performed? What
are each of the bivariable associations tested [list 2
pairs of associations]?
b. Which of the relationships are significant?
c. In everyday language, describe what is shown about the
relationship between age and type of drinking (light/moderate)
among all students? Among drinkers only?
d. How many degrees of freedom are there in the analysis of
religion by type of drinker among all students?...
The columns in the table below contain the Race/Ethnicity of U.S. Public Schools for a recent year, the percentages for the Advanced Placement Examinee Population for that class, and the Overall Stude...
The columns in the table below contain the Race/Ethnicity of
U.S. Public Schools for a recent year, the percentages for the
Advanced Placement Examinee Population for that class, and the
Overall Student Population. Suppose the right column contains the
result of a survey of 1,000 local students from that year who took
an AP Exam. Use 0.5 significance level.
AP Examinee Overall Student Survey Race/Ethnicity Population Frequency Population Asian, Asian American, or Pacific Islander Black or African- American Hispanic or...
1. Use the data in the contingency table to answer the question. Columns Rows 1 2...
1. Use the data in the contingency table to answer the question. Columns Rows 1 2 3 Total 1 36 35 92 163 2 67 57 113 237 Total 103 92 205 400 You wish to test the null hypothesis of "independence"—that the probability that a response falls in any one row is independent of the column it falls in—and you plan to use a chi-square test. You are given that there are 2 degrees of freedom associated with the...
8. Researchers investigated the issue of race and equality of access to clinical trials. The table given in (a) shows the population distribution and the numbers of participants in clinical trials in...
8. Researchers investigated the issue of race and equality of access to clinical trials. The table given in (a) shows the population distribution and the numbers of participants in clinical trials involving lung cancer At a significance level of 0.01, using a P-value test, test the claim that the distribution of clinical trial participants fits well with the population distribution. Is there a race/ethnic group that appears to be very underrepresented? Use the following steps: (a) Complete the expected column...
Test Exam#2 Submit Test This Qu 1 pt 8 of 19 (10 complete) n Help The...
Test Exam#2 Submit Test This Qu 1 pt 8 of 19 (10 complete) n Help The contingency table shows the results of a random sample of former smokers by the number of times they tried to quit smoking before they were habit-free and gender At a 0 05, can you conclude that the number of times they tried to quit before they were habit f ee is related to gender? Perf m the indicated chi quare independence test by completing...
1 pts Question 1 Question 1: Death Penalty. Exercise 14-4. The chi-square for Table 14-3 on...
1 pts Question 1 Question 1: Death Penalty. Exercise 14-4. The chi-square for Table 14-3 on page 138 (see Exercise 14-4 /'a 'in your Exercise Book on page 138) is Table 14-3.PNG [Exercise 14-4 on page 138 is here: exercise 14-4.PNG Exercise 14-4. A speaker at a lecture declares that no statistical evidence whatsoever demonstrates that the death penalty discriminates against minorities. When pressed on the point, she shows a slide that looks like table 14-3.9 The subjects were 326...
Numerator Degrees of Freedom de df, 2 3 4 5 7 8 9 1 2 3...
Numerator Degrees of Freedom de df, 2 3 4 5 7 8 9 1 2 3 4 5 6 7 3 Denominator Degrees of Freedom 10 11 12 13 14 15 16 17 161.45 18.513 10.128 7.7086 6.8079 59874 5.5914 5.3177 5.1174 4.9646 4.8443 4.7472 4.6672 4.6001 4.5431 449-40 4.4513 4.4139 4.3807 4.3512 4.3248 4.3009 4.2793 4.2597 4.2417 4.2252 4.2100 4.1960 4.18.30 4.1709 4.0847 4.0012 3.9201 3.8415 199.50 19.000 9.5521 9.9443 5.7861 5.1433 4.7374 4.4590 4.2565 4.1020 3.9823 3.8853 3.8056...
SPSS Lab Assignment #2 Output Analysis One Descriptives Depression_13 2323 WHITE BLACK AMER IND ASIAN HISPAN...
SPSS Lab Assignment #2 Output Analysis One Descriptives Depression_13 2323 WHITE BLACK AMER IND ASIAN HISPAN Mean 10.0010 10.0930 10.1038 10.1060 10.1062 10.0343 Std. Deviation 24975 27993 25361 27124 27267 26409 95% Confidence interval for Mean Std. ErrorLower Bound Upper Bound 00518 9.9908 10.0111 .00817 10.0770 10.1090 .03699 10.0294 10.1783 04952 10.0047 10.2073 .04158 10.0223 10.1901 00439 10.0257 10.0429 30 43 3617 Total ANOVA Depression 73 Mean Square Sum of Squares 7.230 244.967 1.808 26.651 Between Groups Within Groups Total...
QUESTION 9 Chi-Square The contingency table below contains neighborhood-level homicide data broken down by victim race. Using an a of .05, conduct a five-step hypothesis test to determine whether there is a relationship between neighborhood and victim race. Neighborhood Race Shenandoah Mahanoy North Schuylkill White 34 35 20 Black 12 Hispanic 8 3 0 Question: Do you reject the null hypothesis? 36 18 Yes ОО No
Cross-Tabulation and Chi-Square Test Respondents were asked to assess their current health condition and to report their social class. Data is in the table below Social Class Middle- and Upper Lower- and Working- Class Respondents Tetal Health Status Class Respondents Fair/Poor 220 136 Excellent/Good 472 521 Total 1. What is the independent variable? What is its level of measurement (nominal, ordinal, ratio)? What is the dependent variable? What is its level of measurement (nominal, ordinal, ratio)? 2. Use the frequencies...
1. These questions pertain to Table 1.
a. How many chi-square tests of independence are performed? What
are each of the bivariable associations tested [list 2
pairs of associations]?
b. Which of the relationships are significant?
c. In everyday language, describe what is shown about the
relationship between age and type of drinking (light/moderate)
among all students? Among drinkers only?
d. How many degrees of freedom are there in the analysis of
religion by type of drinker among all students?...
The columns in the table below contain the Race/Ethnicity of
U.S. Public Schools for a recent year, the percentages for the
Advanced Placement Examinee Population for that class, and the
Overall Student Population. Suppose the right column contains the
result of a survey of 1,000 local students from that year who took
an AP Exam. Use 0.5 significance level.
AP Examinee Overall Student Survey Race/Ethnicity Population Frequency Population Asian, Asian American, or Pacific Islander Black or African- American Hispanic or...
8. Researchers investigated the issue of race and equality of access to clinical trials. The table given in (a) shows the population distribution and the numbers of participants in clinical trials involving lung cancer At a significance level of 0.01, using a P-value test, test the claim that the distribution of clinical trial participants fits well with the population distribution. Is there a race/ethnic group that appears to be very underrepresented? Use the following steps: (a) Complete the expected column...
Test Exam#2 Submit Test This Qu 1 pt 8 of 19 (10 complete) n Help The contingency table shows the results of a random sample of former smokers by the number of times they tried to quit smoking before they were habit-free and gender At a 0 05, can you conclude that the number of times they tried to quit before they were habit f ee is related to gender? Perf m the indicated chi quare independence test by completing...
1 pts Question 1 Question 1: Death Penalty. Exercise 14-4. The chi-square for Table 14-3 on page 138 (see Exercise 14-4 /'a 'in your Exercise Book on page 138) is Table 14-3.PNG [Exercise 14-4 on page 138 is here: exercise 14-4.PNG Exercise 14-4. A speaker at a lecture declares that no statistical evidence whatsoever demonstrates that the death penalty discriminates against minorities. When pressed on the point, she shows a slide that looks like table 14-3.9 The subjects were 326...
Numerator Degrees of Freedom de df, 2 3 4 5 7 8 9 1 2 3 4 5 6 7 3 Denominator Degrees of Freedom 10 11 12 13 14 15 16 17 161.45 18.513 10.128 7.7086 6.8079 59874 5.5914 5.3177 5.1174 4.9646 4.8443 4.7472 4.6672 4.6001 4.5431 449-40 4.4513 4.4139 4.3807 4.3512 4.3248 4.3009 4.2793 4.2597 4.2417 4.2252 4.2100 4.1960 4.18.30 4.1709 4.0847 4.0012 3.9201 3.8415 199.50 19.000 9.5521 9.9443 5.7861 5.1433 4.7374 4.4590 4.2565 4.1020 3.9823 3.8853 3.8056...
SPSS Lab Assignment #2 Output Analysis One Descriptives Depression_13 2323 WHITE BLACK AMER IND ASIAN HISPAN Mean 10.0010 10.0930 10.1038 10.1060 10.1062 10.0343 Std. Deviation 24975 27993 25361 27124 27267 26409 95% Confidence interval for Mean Std. ErrorLower Bound Upper Bound 00518 9.9908 10.0111 .00817 10.0770 10.1090 .03699 10.0294 10.1783 04952 10.0047 10.2073 .04158 10.0223 10.1901 00439 10.0257 10.0429 30 43 3617 Total ANOVA Depression 73 Mean Square Sum of Squares 7.230 244.967 1.808 26.651 Between Groups Within Groups Total...
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