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Part III Data table 3 Time 1 2 3 4 35 6 7 8 9 10 11 12 13 14 15 16 17 Hot water temperature(Th) Celsius 75 68 66 65 64 63 62
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I have solved your problem which is shown below:

Question 8: What happens to the temperature of the water in the two containers? How does that happen?

Answer: As we can see from the table that the container which is at higher temperature losses its heat while the container at low temperature gaining the heat from the high temperature and its temperature starts rising as the time passes. This happens because the hot water started to heat the container which then transfer its heat to the cold water and cold water started gaining the heat and hot water started losing the heat.

Question 9: Plot a graph Temperature Vs time for the duration of step 3.

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Question 10: Do the two graphs meet? Why or why not?

Answer: In the given time interval graphs do not meet but as the time passes then after some time then both the containers acquire equilibrium temperature and at that point both the graphs will meet. Because the hot water graph is continuously decreasing and cold water graph is continuously increasing and at equilibrium (when both water containers have same temperature) meet.

Question 11: What phenomena describes what happen in step 3?

Answer: The process that is happing is the heat flow from higher temperature body to low temperature body. This is mode of transfer of heat by conduction. As the both containers are not in contact so they transfer their heat via glass beaker as high temperature water molecules starts vibrating about its position then the heat gets transfer to the container which further transfer to the low energy molecules to achieve equilibrium for whole system.

Question 12: What information you can deduce from the graph?

Answer: From the graph we can determine the rate of flow of heat from high temperature water to the cold water. We know Q = mcΔT and the rate of flow of heat \frac{\mathrm{d} Q}{\mathrm{d} t}=-k(T-T_{0}) by measuring the mass of the water present in containers we can find rate at which heat gets transfer.

I hope you like it. Thank you

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