Question

a household refrigiratotor

Problems 15 and 16 are based on the following description A household referater runs 20 minutes in every hour and removes heat from the food compartment during this running time 1200 The COP of the refrigerator is 2.1. The power the refrigerator draws when running in kW is closer to 0.16 0.23 O 066 0.02 0.00 0.27 2.1 1 pts Question 16 Assuring a cost of electricity of 0.10 $/kWh, the cost in $ to operate this refrigerator per day is closer to 12 0.45 0.89 1.5 MacBook Pro Å 3 E R

Answer 1

Answer: 0.16 kW

For a refrigerator, COP = Q_L/W_in

where Q_L is the desired cooling and W_in is the work input.

Given, COP = 2.1, Q_L = (1200 kJ/60 mins)*(20 mins) = 400 kJ

So, W_in = 400/2.1 = 190.48 kJ which is the work input in 20 minutes.

So, power drawn = 190.48/(20*60) = 0.158 kW which is close to 0.16 KW.