Solution,
degrees of freedom = 9
P( -t0 < t < t0) = 0.99
= P(t < t0) - P(t <-t0 ) = 0.99
= 2P(t < t0) - 1 = 0.99
= 2P(t < t0) = 1 + 0.99
= P(t < t0) = 1.99 / 2
= P(t < t0) = 0.995
= P(t < 3.250) = 0.995
= t0 ± 3.250
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