Question

The cost of a leading liquid laundry detergent in different sizes is given below. Size (ounces) 16 32 64 200 Cost ($) 3.49 4.

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Answer #1

Part (C)

Computational Table:

Size (X) Cost (Y) X2 Y2 XY
16 3.49 256 12.18 55.84
32 4.39 1024 19.27 140.48
64 5.29 4096 27.98 338.56
200 10.29 40000 105.88 2058
Total 312 23.46 45376 165.3204 2592.88

Calculation:

312 Χ. ΣΧί = 78 η 4

\bar{Y} = \frac{\sum Yi}{n} = \frac{23.46}{4} = 5.865

For Slope:

b = \frac{n\sum XY - (\sum X)(\sum Y)}{n\sum X^2 - (\sum X)^2}

b = \frac{4*2592.88 - (312)(23.46)}{4*45376 - (312)^2}

b = 0.036

For Intercept:

a = \bar{Y} - b\bar{X}

a = 5.865 - 0.036 * 78

a = 3.036

Therefore, the least square regression line would be,

Ý = a+b(X)
\hat{Y} = 3.036 + 0.036 (X)

d)

Correlation coefficient (r):

r = \frac{n\sum xy - (\sum x)(\sum y)}{\sqrt{n\sum x^2 - (\sum x)^2}\sqrt{n\sum y^2 - (\sum y)^2}}

r = \frac{4*2592.88 - (312)(23.46)}{\sqrt{4*45376 - (312)^2}\sqrt{4*165.32 - (23.46)^2}}

r = 0.9990

Is it significant,

Correlation coefficient (r) value is near to +1, i.e. there is Strong Postive Correlation between size (Ounces) and Cost ($)

ANSWER: A
A. Yes

Part (e)

The least square regression line would be,

Ý = a+b(X)
\hat{Y} = 3.036 + 0.036 (X)

Put X = 50

\hat{Y} = 3.036 + 0.036*50

\hat{Y} = 4.85

Part (f)

The least square regression line would be,

Ý = a+b(X)
\hat{Y} = 3.036 + 0.036 (X)

Put X = 80

\hat{Y} = 3.036 + 0.036*80

\hat{Y} = 5.94

i)

For Slope:

b = \frac{n\sum XY - (\sum X)(\sum Y)}{n\sum X^2 - (\sum X)^2}

b = \frac{4*2592.88 - (312)(23.46)}{4*45376 - (312)^2}

b = 0.036

As the number of ounces of liquid laundry detergent increased by one unit, the detergent cost increased by 0.036 dollars.

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