Question

Of nine executives in a business firm, four are married, three have never married, and two qe divorced. Three of the executives are to be selected for promotion. Let Y, denote the number of married executives and y, denote the number of never-married executives among the the selected for promotion. Assume that the three are randomly selected from the nine available We determined that the joint probability distribution of Y, and y, is given by (C)(-;-) P(Y , Y2) - where y, and y, are integers, O SY, S3, OS Y, 53 and 1 SYA+Y53. We also determined that the marginal probability distribution of V, is a hypergeometric distribution with N 9, 3, and r Find the expected number of married executives among the three selected for promotion married executives

Answer 1

here this is hypergeometric distribution with parameter:
sample size n=3
population N=9
success size k=4
expected number μ=nk/N =3*4/9=1.333 married executives