Question

Let f() = 1+1 (a) Identify the domain off Instructions: Fill in the blank separating values with commas, if necessary. If the domain is all real numbers, type none The domain of fis {x ERT (b) Identify any intercepts Instructions: Enter intercepts as points using brackets, [u, y). Type none if f does not have an intercept of the prescribed type The y-interceptis 3 List the x-intercepts separating entries by commas, if necessary (c) Identify any asymptotes Instructions: List all vertical and horizontal asymptotes separating entries by commas, if necessary.

Answer 1

f(x) = 4+1 The domain off is {XER | x + [{-1} la) The y intercept is 10,1 put x=0 in F(x) = 4+1 then y=f(x) = 1 The graph of f has no x-intercept. @) The vertical asymptote is x=-1, denominaton is equal to zero, i.l, x+1=0 x=-1 is the As x + + y = f(a) o then Y=0 horizontal asymptote. [(-00,-1], the graph is bellow the x-axis. (-1,400 graph is above the x-axis. (d) the e y y intercept 0,1) V horizontal asymptote N=- vertical asymptote Groaph for har