Question

Question 3 The mechanism is used on a machine for the manufacturing of a wire product. Because of the rotational motion of link AB and the, sliding of block F, the segmental gear lever DE undergoes general plane motion. If AB is rotating at WAB = 5 rad/s, determine the velocity of point E at the instant shown. 50 mm 20 mm F 20 mm 50 mm 200 mm B 45 WAB = 5 rad/

Using instantaneous centre of rotation method.

Answer 1

soin FBD of CB :- 20mm Vc now, Voa MAB X VAB. 2 comm us' WBC 5x50 JB 250 MM mm/s Ves VR + Vet Vele. Vcs 250 + WBC (200) © O = 250 sinus'- Wec (200) sinus' Efy=0 Ef =0 Vc:250 cos 45' + Wec (200) Co 45 from 40; WBC *141.421 = 250 sinus VE Woc = 1.25 rad read/ mm/s HUDE vo 353.553 Up= Vct vo up/c = 353.553 + [1.25*20) VO 353.553 + 250 + 20 WDE * Ehe= 0 ; VO = 353. 1553 .mm/sec 1:25x20 = 0 ; WDE - = 1:25 efy reads 20 Ves VD + VELD 353.553 Co 1.25 +50 VEx : Veloso 353.553.1.25 150 x 45 Vex = CS Sçantted with CamScanne 309.358 mm Here - An

Vey VE fin 0 Ot 1.25x50xSin 45 Vey 44.194 mm/sec ? m/sec YANS VE: V Vem? + Vey? 309.3582744.jqy2 VE 312.4987 mm/se - Answers CS Scannedykitchen sezna Scanner